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Citrus2011 [14]

3 years ago

12

(4x^2+35x+54)/(x+7) Helppp

1 answer:

Amanda [17]3 years ago

3 0

Hello there! The following picture below should assist you with answering your question. Let me know if you find any errors or cannot read my writing, and I will review and fix them as required. Thanks!

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What is the value of x?

inn [45]

MN = MA + AN =67.2m

MA + 3.2m = 67.2m

MA = 64m

Similary,

MP = 81.9

As
AB || NP

Then by Thale's theorem,

$\frac{MA}{MN} = \frac{ MB}{MP } \\ \\ \frac{64}{67.2} = \frac{x}{81.9} \\ \\ x = \frac{64}{62.7} \times 81.9 = 83.59$

4 0

3 years ago

Bill sees two boxes of baseball cards at a card show. The first box has 150 cards for $12.55.The second box has 120 cards for $9

Grace [21]

Answer: Cards in second box are cheaper.

Step-by-step explanation:

We are told that the first box has 150 cards for $12.55. Therefore, the cost of one card would be:

= $12.55 / 150

= $0.084.

The second box has 120 cards for $9.60. Therefore, the cost if one card would be:

= $9.60 / 120

= $0.08

Therefore, the cards in the second box are cheaper.

6 0

3 years ago

Will make brainliest if answered correctly

stealth61 [152]

Answer:

3.75Km

Step-by-step explanation:

to find Average speed you do distance over time so it would be 225/25=3.75

3 0

3 years ago

Read 2 more answers

A triangle has side lengths of 23 in, 19 in, and 37 in

ArbitrLikvidat [17]

Formula is bh/2.
So, 23*19/2 = 218.5

4 0

3 years ago

What is the solution of the system? Use elimination.

sweet [91]

Answer:

The solutions to the system of the equations by the elimination method will be:

$x=2,\:z=-1,\:y=2$

Step-by-step explanation:

Given the system of the equations

$2x\:+\:2y\:+z\:=\:7$

$-x-\:y\:+z\:=\:-5$

$x+3y-4z=12$

solving the system of the equations by the elimination method

$\begin{bmatrix}2x+2y+z=7\\ -x-y+z=-5\\ x+3y-4z=12\end{bmatrix}$

$\mathrm{Multiply\:}-x-y+z=-5\mathrm{\:by\:}2\:\mathrm{:}\:\quad \:-2x-2y+2z=-10$

$\begin{bmatrix}2x+2y+z=7\\ -2x-2y+2z=-10\\ x+3y-4z=12\end{bmatrix}$

$-2x-2y+2z=-10$

$+$

$\underline{2x+2y+z=7}$

$3z=-3$

$\begin{bmatrix}2x+2y+z=7\\ 3z=-3\\ x+3y-4z=12\end{bmatrix}$

$2x+6y-8z=24$

$-$

$\underline{2x+2y+z=7}$

$4y-9z=17$

$\begin{bmatrix}2x+2y+z=7\\ 3z=-3\\ 4y-9z=17\end{bmatrix}$

Rearranging the equations

$\begin{bmatrix}2x+2y+z=7\\ 4y-9z=17\\ 3z=-3\end{bmatrix}$

solve $3z=-3$ for z:

$z=-1$

$\mathrm{For\:}4y-9z=17\mathrm{\:plug\:in\:}z=-1$

solve $4y-9\left(-1\right)=17$ for y:

$4y-9\left(-1\right)=17$

$4y+9=17$

$4y=8$

$y=2$

$\mathrm{For\:}2x+2y+z=7\mathrm{\:plug\:in\:}z=-1,\:y=2$

solve $2x+2\cdot \:2-1=7$ for x:

$2x+2\cdot \:2-1=7$

$2x+3=7$

$2x=4$

$x=2$

Therefore, the solutions to the system of the equations by the elimination method will be:

$x=2,\:z=-1,\:y=2$

5 0

3 years ago