Answer:
Step-by-step explanation:
Use distributive property.
Set the height to h, and the width to w.
We know that wh=190 and h=2w-1.
Substituting 2w-1 for h, we have:
w(2w-1)=190
So:
2w^2-w-190=0
Factoring this equation, we get (2w+19)(w-10)=0. The solutions to this equation are -9.5 and 10, but clearly the width must be positive, Substituting 10 for the width, we get 10*2-1=19 for the height.
Both of these conditions must be true in order for the assumption that the binomial distribution is approximately normal. In other words, if and then we can use a normal distribution to get a good estimate of the binomial distribution. If either np or nq is smaller than 5, then a normal distribution wouldn't be a good model to use.
side note: q = 1-p is the complement of probability p
Yes it is, any decimal after the number one will be bigger than one