Answer:
The missing frequencies are x = 8 and y = 43.
Step-by-step explanation:
Median Value =70
Then the median Class =60-80
Let the missing frequencies be x and y.
Given: Total Frequncy = 200 , Median = 46

From the table
Here, n = 200
n/2 = 100
Lower Class Boundary of the median class, l=60
Frequency of the median class(f) =66
Cumulative Frequency before the median class, f=42+x
Class Width, h=10


200=149+x+y
200=149+8+y
y=200-(149+8)
y=43
Hence, the missing frequencies are x = 8 and y = 43.
Answer:
697.2
Step-by-step explanation:
Answer:
x = 20
Step-by-step explanation:
I don't see a y in the diagram.
The 3 angles x, 90 and (4x - 10) lie on the line EF and sum to 180°, so
x + 90 + 4x - 10 = 180, that is
5x + 80 = 180 ( subtract 80 from both sides )
5x = 100 ( divide both sides by 5 )
x = 20
Answer
N-9=-18
Move the -9 to -18 and add those cuz if there’s two negative u have to add
Add 9