Question

Given f (x) = 2 (x-1)^2 + 3x -7, evaluate f (0) and f (-3)

Answer 1

Answer:

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Answer 2

Answer:

$f(x) =2 {(x - 1)}^{2} + 3x - 7 \\ f(0) = 2{(0 - 1)}^{2} + 3(0) - 7 \\ f(0) = 2 {( - 1)}^{2} + 0 - 7 \\ f(0) = 2(1)- 7 \\ f(0) = 2 - 7 \\ f(0) = - 5$

__o_o__

$f(x) = 2 {(x - 1)}^{2} + 3x - 7 \\ f( - 3) = 2 {( - 3 - 1)}^{2} + 3( - 3) - 7 \\ f( - 3) = 2 {( - 4)}^{2} - 9 - 7 \\ f( - 3) = 2(16) - 16 \\ f( - 3) = 32 - 16 \\ f( - 3) = 16$

I hope I helped you^_^