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Tamiku [17]
3 years ago
13

How long does it take for carbon monoxide to dissipate?

Chemistry
1 answer:
ohaa [14]3 years ago
5 0

Answer:The half-life of carboxyhemoglobin in fresh air is approximately 4 hours. To completely flush the carbon monoxide from the body requires several hours, valuable time when additional damage can occur.

Symptoms: Dizziness; Unconsciousness; Confusion...

Explanation:

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Can Hydrocyanic acid be a Lewis Acid? What about a Lewis Base?
FinnZ [79.3K]

HCN is a Bronsted acid; it can dissociate into H+ and CN-. And H+ is a Lewis acid because it accepts election pairs. ... In order for H+ and CN- to be formed, Hydrogen in HCN donates its electrons to Carbon. So in this sense, Hydrogen is the lewis base and Carbon is the lewis acid.

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A lever with a mechanical advantage greater then 1 is used to
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<span>. increase distance , increase force.</span>
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6b<br> Which of the following is a starting compound during<br> cellular respiration?
Rus_ich [418]

Answer: Oxygen and glucose.

Explanation:

Oxygen and glucose are both reactants in the process of cellular respiration. The main product of cellular respiration is ATP; waste products include carbon dioxide and water.Jun 1, 2020

3 0
3 years ago
Write the chemical reactions for a weak acid and a strong acid.
Fiesta28 [93]

Answer:

Weak acid and base solutions contain multiple charged and uncharged species in dynamic equilibrium. Strong acids and strong bases refer to species that completely dissociate to form ions in solution.

Explanation:

8 0
3 years ago
Calculate the heat absorbed by the water in a calorimeter when 175 grams of lead cools from 125.0°C to 22.0°C. The specific heat
Iteru [2.4K]

Answer:

Q = 233.42 J

Explanation:

Given data:

Mass of lead = 175 g

Initial temperature = 125.0°C

Final temperature = 22.0°C

Specific heat capacity of lead = 0.01295 J/g.°C

Heat absorbed by water = ?

Solution:

Heat  absorbed by water is actually the heat lost by the metal.

Thus, we will calculate the heat lost by metal.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 22.0°C - 125.0°C

ΔT = -103°C

Q = 175 g × 0.01295 J/g.°C×-103°C

Q = -233.42 J

Heat absorbed by the water is 233.42 J.

5 0
3 years ago
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