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scoray [572]
3 years ago
13

Sheldon is making a steak for dinner. at first, the steak is at room temperature, 72°Friday. then, he places it on the grill, wh

ere it's temperature increase at a rate of 3 1/5°F for each minutes. after ten minutes, he removed The steak from the grill and let's it cool for 7 minutes on the counter. while it is siting on The counter, it's cool at a rate of 4 2/7°F each minutes. what was the net change in the Temperature of the steak from before it was cooked and when it was served?
Mathematics
1 answer:
ohaa [14]3 years ago
6 0
We start qt 72 degrees,
3 1/5 = 16/5 = 3.2 x 10 minutes = 32 degrees.
72 + 32 = 104 degrees. 
Cool Time:
 4 2/7 = 30/7 = 4.28571429 x 7 minutes = 30 degrees.
104 - 30 = 74
So we went from 72 to 74 degrees, that is a 2 degree difference. 
This is what i got, i hope i understood the question correctly.v
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If p varies directly with T and p =105 when T=400.Find p when T =500
kumpel [21]

Answer:

<h3>p = 131.25</h3>

Step-by-step explanation:

The variation p varies directly with T is written as

p = kT

where k is the constant of proportionality

To find p when T =500 we must first find the formula for the variation

That's

when p = 105 and T = 400

105 = 400k

Divide both sides by 400

<h3>k =  \frac{21}{80}</h3>

So the formula for the variation is

<h2>p =  \frac{21}{80} T</h2>

when

T = 500

Substitute it into the above formula

That's

p =  \frac{21}{80}  \times 500

Simplify

The final answer is

<h3>p = 131.25</h3>

Hope this helps you

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