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2 + 2 + x - 7 = 21
11 + x = 21
We have to subtract 11 on both sides to isolate x
11 ( - 11 ) + x = 21 ( - 11 )
11 and 11 cancels out
x = 10
Answer: I think it is (6.5, 8).
Step-by-step explanation:
I don't know if you had any choices, but I graphed it on Desmos and that was the closest point. I hope this helps!! :)
The picture shows the answer I got!
Also! For the future, I use a site called
math way and it is great for problems like these.
multiply 4.5 and 10-1kgget the answer and multiply it to the answer of 3.2 and 106 which you get by multiplying 3.2 and 10kg
Answer: 1. P = 1/64
2. P = 1/32
3. P = 1/8
Step-by-step explanation:
In genetics, an ofspring inherits one copy of an allele of each parent, which can be described in the tables below called Punnett Square:
For crossing Aa x Aa:
A a
A AA Aa
a Aa aa
For crossing Bb x Bb:
B b
B BB Bb
b Bb bb
For crossing Cc x Cc:
C c
C CC Cc
c Cc cc
We can separate them because they are assorted independently.
For offspring with <u>genotype</u> <u>AABBcc</u>, probability will be:
P(AA) = 1/4
P(BB) = 1/4
P(cc) = 1/4
As all three probabilities has to happen at the same time, it is a "E" rule:
P(AABBcc) = 
P(AABBcc) = 1/64
Probability for the individual to be AABBcc is 1/64 or 1.56%.
<u>Genotype</u> <u>AaBBcc</u>:
P(Aa) = 2/4 = 1/2
P(BB) = 1/4
P(cc) = 1/4
P(AaBBcc) = 
P(AaBBcc) = 1/32
Probability for the individual to be AaBBcc is 1/32 or 3.12%
<u>Genotype</u> <u>AaBbCc</u>:
P(Aa) = 1/2
P(Bb) = 1/2
P(Cc) = 1/2
P(AaBbCc) = 
P(AaBbCc) = 1/8
Probability for the individual to be AaBbCc is 1/8 or 12.5%.