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lara31 [8.8K]
3 years ago
10

Which types of polygons are the faces of a octahedron

Mathematics
2 answers:
shutvik [7]3 years ago
7 0

Answer:(i think)

Equilateral triangles

ioda3 years ago
7 0

Answer:

A regular octahedron has 8 congruent faces that are congruent equilateral triangles, 12 congruent edges, and 6 vertices; an edge is a line segment formed by the intersection of two adjacent faces; a vertex for a regular octahedron is a point where 4 edges meet.

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One half of a number y is more than 22
NARA [144]

Answer:

1/2xy > 22

Step-by-step explanation:

It's not really clear what your asking, but I assume your asking for the equation put into numbers. I don't believe that they are asking for you to find the number though.

8 0
3 years ago
If x - 3 Is a factor P(x) = x ^ 3 - 7x ^ 2 + 15x - 9, which of the following represents the complete factorization for P(x) ?
sattari [20]

the answer is c, i just got this question

3 0
3 years ago
This is finding exact values of sin theta/2 and tan theta/2. I’m really confused and now don’t have a clue on how to do this, pl
Lostsunrise [7]

First,

tan(<em>θ</em>) = sin(<em>θ</em>) / cos(<em>θ</em>)

and given that 90° < <em>θ </em>< 180°, meaning <em>θ</em> lies in the second quadrant, we know that cos(<em>θ</em>) < 0. (We also then know the sign of sin(<em>θ</em>), but that won't be important.)

Dividing each part of the inequality by 2 tells us that 45° < <em>θ</em>/2 < 90°, so the half-angle falls in the first quadrant, which means both cos(<em>θ</em>/2) > 0 and sin(<em>θ</em>/2) > 0.

Now recall the half-angle identities,

cos²(<em>θ</em>/2) = (1 + cos(<em>θ</em>)) / 2

sin²(<em>θ</em>/2) = (1 - cos(<em>θ</em>)) / 2

and taking the positive square roots, we have

cos(<em>θ</em>/2) = √[(1 + cos(<em>θ</em>)) / 2]

sin(<em>θ</em>/2) = √[(1 - cos(<em>θ</em>)) / 2]

Then

tan(<em>θ</em>/2) = sin(<em>θ</em>/2) / cos(<em>θ</em>/2) = √[(1 - cos(<em>θ</em>)) / (1 + cos(<em>θ</em>))]

Notice how we don't need sin(<em>θ</em>) ?

Now, recall the Pythagorean identity:

cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1

Dividing both sides by cos²(<em>θ</em>) gives

1 + tan²(<em>θ</em>) = 1/cos²(<em>θ</em>)

We know cos(<em>θ</em>) is negative, so solve for cos²(<em>θ</em>) and take the negative square root.

cos²(<em>θ</em>) = 1/(1 + tan²(<em>θ</em>))

cos(<em>θ</em>) = - 1/√[1 + tan²(<em>θ</em>)]

Plug in tan(<em>θ</em>) = - 12/5 and solve for cos(<em>θ</em>) :

cos(<em>θ</em>) = - 1/√[1 + (-12/5)²] = - 5/13

Finally, solve for sin(<em>θ</em>/2) and tan(<em>θ</em>/2) :

sin(<em>θ</em>/2) = √[(1 - (- 5/13)) / 2] = 3/√(13)

tan(<em>θ</em>/2) = √[(1 - (- 5/13)) / (1 + (- 5/13))] = 3/2

3 0
3 years ago
Find the values of x and y.
babunello [35]

Answer:

x=21°. :Angles subtended by the same arc

y=42°. :180-(117+21),angles subtended by the same arc

8 0
3 years ago
Make doubles.add. 5+6 __+_+_ so,5+6=11
RUDIKE [14]
If you want 2 numbers, you have: 1+10, 2+9, 3+8, and so on. If you need 3 numbers you have 1+1+9, 1+2+8, 2+2+7, and so on.
5 0
3 years ago
Read 2 more answers
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