Answer:
he bought the t shirt for rs 1880
Yea because it’s increasing
To find the interquartile range, you will list the data that is presented in the stem and leaf plot.
Find the median of the data (30.5)
Find the median of the lower half and the median of the upper half.
Subtract these two values.
The data are <u>20</u>, 25, 30, 30, 31, 40, 41, <u>49</u>.
27.5 40.5
40.5-27.5 = 13
The interquartile range is 13.
Number of solutions: no roots
Type of solution: Not Real
Step-by-step explanation:
We need to identify the number of solutions and their types using the discriminant.
We are given: ![40x=10x^2+41\\](https://tex.z-dn.net/?f=40x%3D10x%5E2%2B41%5C%5C)
Rearranging:
![40x-10x^2-41=0\\10x^2-40x+41=0](https://tex.z-dn.net/?f=40x-10x%5E2-41%3D0%5C%5C10x%5E2-40x%2B41%3D0)
Discriminant can be found by: ![b^2-4ac](https://tex.z-dn.net/?f=b%5E2-4ac)
where b=-40, a=10 and c=41
Putting values:
![b^2-4ac\\=(-40)^2-4(10)(41)\\=1600-1640\\=-40\\](https://tex.z-dn.net/?f=b%5E2-4ac%5C%5C%3D%28-40%29%5E2-4%2810%29%2841%29%5C%5C%3D1600-1640%5C%5C%3D-40%5C%5C)
So, Discriminant is -40
If the discriminant is less than zero i.e -40 then there are no real roots.
So, Number of solutions: no roots
Type of solution: Not Real
Keywords: discriminant
Learn more about discriminant at:
#learnwithBrainly
Answer:
A
The test statistics is ![t = -1.7](https://tex.z-dn.net/?f=t%20%20%3D%20-1.7)
B
The Null and Alternative hypothesis are
and ![H_a : \mu \ne 47.2](https://tex.z-dn.net/?f=H_a%20%3A%20%20%5Cmu%20%5Cne%20%2047.2)
Step-by-step explanation:
From the question we are told that
The population mean is ![\mu = 47.2 miles/gallon(MPG)](https://tex.z-dn.net/?f=%5Cmu%20%20%3D%20%2047.2%20miles%2Fgallon%28MPG%29)
The sample size is ![n = 250 \ van](https://tex.z-dn.net/?f=n%20%3D%20%20250%20%5C%20van)
The sample mean is ![\= x = 47.0](https://tex.z-dn.net/?f=%5C%3D%20x%20%20%3D%20%2047.0)
The sample standard deviation is ![\sigma = 1.9](https://tex.z-dn.net/?f=%5Csigma%20%20%3D%20%201.9)
The level of significance is ![\alpha = 0.02](https://tex.z-dn.net/?f=%5Calpha%20%20%3D%20%200.02)
Given that the value which the manufacturer gave the automobile is 47.2 and it is believed that this is not correct, then
The Null Hypothesis is
![H_o : \mu = 47.2](https://tex.z-dn.net/?f=H_o%20%20%3A%20%20%5Cmu%20%3D%2047.2)
The alternative Hypothesis is
![H_a : \mu \ne 47.2](https://tex.z-dn.net/?f=H_a%20%3A%20%20%5Cmu%20%5Cne%20%2047.2)
The test statistics can be mathematically evaluated as
![t = \frac{\= x- \mu}{\frac{\sigma }{\sqrt{n} } }](https://tex.z-dn.net/?f=t%20%20%3D%20%20%5Cfrac%7B%5C%3D%20x-%20%5Cmu%7D%7B%5Cfrac%7B%5Csigma%20%7D%7B%5Csqrt%7Bn%7D%20%7D%20%7D)
substituting values
![t = \frac{\= 47- 47.2}{\frac{1.9 }{\sqrt{250} } }](https://tex.z-dn.net/?f=t%20%20%3D%20%20%5Cfrac%7B%5C%3D%2047-%2047.2%7D%7B%5Cfrac%7B1.9%20%7D%7B%5Csqrt%7B250%7D%20%7D%20%7D)
![t = -1.7](https://tex.z-dn.net/?f=t%20%20%3D%20-1.7)