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riadik2000 [5.3K]
3 years ago
5

Five times a number is greater than 25

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
3 0
Hello! your answer will be “all real numbers above 5.” hope this helps!
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Consider a solid spherical ball made of wood. Suppose a hole is bored (drilled) vertically through the center of the ball and th
lbvjy [14]

Answer:

The volume of solid is 268.08 inches cube.

Step-by-step explanation:

The solid spherical ball has height 8 inches that means the diameter of the sphere is 8 inches. So, the radius will be the half of diameter. Thus, radius is 4 inches.

Now use below formula to find the volume of solid sphere.

Volume = \frac{4}{3}\pi r^{2} \\Volume = \frac{4}{3}\pi (4)^{2} \\Volume = 268.08 \ in^{3}

Therefore, the volume of solid is 268.08 inches cube.

5 0
3 years ago
A holiday toy drive is putting together baskets for children they’re 84 toys and 56 books if each basket or see the same number
BaLLatris [955]

Answer:

28

Step-by-step explanation

we can use Greatest common divisor to solve

84 and 56 Greatest common divisor is 28(you can try)

so is 28 basket and every basket has 3 toys and 2 books

3 0
3 years ago
X 2x+24<br> Equation <br> Plz help
Nataly_w [17]

Answer:

x + 2x + 24 = 180 \\ 3x = 180 - 24 \\ 3x = 156 \\ x = 52

8 0
3 years ago
Read 2 more answers
I have 100 items of product in stock. The probability mass function for the product's demand D is P(D=90)=P(D=100)=P(D=110)=1/3.
masya89 [10]

Answer:

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 96.667

The variance is 22.222

b) The probability mass function for the unfilled demand due to lack of stock is

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 3.333

The variance is 33.333

Step-by-step explanation:

If the demand is higher than 100, then you will sell 100 items only. Thus, there is a probability of 1/3+1/3 = 2/3 that you will sell 100 items, while there is a probability of 1/3 that you will sell 90.

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 1/3 * 90 + 2/3 * 100 = 290/3 = 96.667

The variance is V(X) = E(X²)-E(X)² = (1/3*90² + 2/3*100²) - (290/3)² = 200/9 = 22.222

b) If order to be unfilled demand, you need to have a demand of 110, which happens with probability 1/3. In that case, the value of the variable, lets call it Y, that counts the amount of unfilled demand due to lack of stock is 110-100 = 10. In any other case, the value of Y is 0, which would happen with probability 1-1/3 = 2/3. Thus

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 2/3 * 0 + 1/3 * 10 = 10/3 = 3.333

The variance is 2/3*0² + 1/3*10² = 100/3 = 33.333

4 0
3 years ago
Make x the subject of the formula y = m x + b
NemiM [27]
Y-b/m=x (you just move everything to the other side)
5 0
3 years ago
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