Help pls plsssssssss

Mathematics

1 answer:

Salsk061 [2.6K]2 years ago

4 0

Answer:

$area = 0.5 \times height \times width \\ = 0.5 \times (x + 2) \times (x +2 - 7) = 4 \\ 4 \div 0.5 = (x + 2)(x - 5) = 8 \\ {x}^{2} - 3x - 10 = 8 \\ {x}^{2} - 3x - 18 = 0 \\ (x - 6)(x + 3) = 0 \\ x = - 3 \\ x = 6$

You might be interested in

What are the zero(s) of the function f(x)=<img src="https://tex.z-dn.net/?f=%5Cfrac%7B4x%5E%7B2%7D-36x%20%7D%7Bx-9%7D" id="TexFo

Contact [7]

Answer:

Step-by-step explanation:

The function will be zero when the numerator is equal to 0. So, set the numerator equal to 0 and solve:

$0 = 4 {x}^{2} - 36x$

I will use the quadratic formula:

$\frac{ 36 + \sqrt{ {36}^{2} - 4(4)(0)} }{2(4)} \\ \frac{ 36 + 36}{8} = 9$

Therefore, x = 9 is a 0. Let's check with subtracted root now:

$\frac{ 36 - \sqrt{ {36}^{2} - 4(4)(0)} }{2(4)} \\ \frac{ 36 - 36}{8} = 0$

It appears 0 is also a root.

Therefore, the answer is D.

7 0

3 years ago

The product 3/4 times 1/2 will be less than or greater than 3/4

Komok [63]

Answer:

less

Step-by-step explanation:

first you would multiply and get 4/8, which simplifies to 1/2, which would be 2/4, which is less than 3/4

3 0

3 years ago

Read 2 more answers

John's car is stopped at a red light. When the light changes, the car accelerates to 45 miles per hour in 15 seconds. What is th

Ede4ka [16]

Initial velocity of John's car (V1) = 0 miles per hour
Final velocity of John's car (V2) = 45 miles per hour
Time taken for acceleration = 45 seconds
Then
Acceleration = (V2 - V1)/Time taken
   = (45 - 0)/15 miles per hour per second
   = 45/15 miles per hour per second
   = 3 miles per hour per second.
So the approximate rate of change in the miles per hour that John's car accelerated is 3 miles per hour per second. The correct option among all the options given in the question is option "A".

5 0

3 years ago

Read 2 more answers

I have five questions and I need some help. please help

Step2247 [10]

The answer to the question