We have:
5(x + 7) = 85 |divide both sides by 5
x + 7 = 17 |subtract 7 from both sides
x = 10
Answer:
0.34134
Step-by-step explanation:
In other to solve for this question, we would be using the z score formula
z = (x - μ) / σ
x = raw score
μ = mean
σ = Standard deviation
We are told in the question to find the probability that a worker selected at random makes between $350 and $400
let x1 = 350 and x2= 400 with the mean μ = 400 and standard deviation σ = $50.
z1 = (x1 - μ) / σ = (350-400) / 50 = -1
z2 = (x2 - μ) / σ = (400 - 400) / 50 = (0/50) = 0
From tables, P(z <= -1) = 0.15866
P(z <= 0) = 0.5
Then, the probability would give us, P(-1 ≤ z ≤ 0) =0.5 - 0.15866 =
0.34134
Hence, The probability that a worker selected at random makes between $350 and $400 = 0.34134
Answer:
Weight=2.835
Step-by-step explanation:
See the attached picture for explanation.
D because is just did the math and that's what I got
The data-set that places 22.6 as an outlier is given as follows:
2.4, 5.3, 3.5, 22.6, 1.8, 2.1, 4.6, 1.9
<h3>When a measure is considered an outlier in a data-set?</h3>
A measure is considered an outlier in a data-set if it is very far from other measures, especially in these two cases:
- If the measure is considerably less than the second smallest value.
- If the measure is considerably more than the second highest value.
In this problem, he data-set that places 22.6 as an outlier is given as follows:
2.4, 5.3, 3.5, 22.6, 1.8, 2.1, 4.6, 1.9.
The second highest value is 5.3, which is considerably less than 22.6, hence 22.6 is an outlier in the data-set.
More can be learned about statistical outliers at brainly.com/question/9264641
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