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frutty [35]
2 years ago
10

Please this is URGENT!!!!!! need it in the next 5 mins!!!!!!!

Mathematics
1 answer:
Tanya [424]2 years ago
4 0

Answer:

distance: 7.81 miles

Explanation:

<u>simply use distance formula:</u>  \sf \sqrt{(y_2 -y_1)^2 + (x_2-x_1)^2}

  • coordinates: (4, 3), (10, 8)

<u>using the equation:</u>

\hookrightarrow  \sf \sqrt{(8-3)^2+(10-4)^2}

\hookrightarrow \sf \sqrt{(5)^2+(6)^2}

\hookrightarrow \sf \sqrt{25+36}

\hookrightarrow \sf \sqrt{61}

\hookrightarrow \sf 7.81  \ miles

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Centimeter because millimeter is way to small and meter and kilometer are far to big
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3 years ago
Carlos and Ethan noticed that both proportional relationships and linear functions form a straight line when graphed. Carlos cla
Andrews [41]

Answer:

B. Ethan is correct because all proportional relationships form a straight line and go through the origin and linear functions are linear, but they don’t all go through the origin so they are not always proportional.

Step-by-step explanation:

So a proportional relationship is just a special kind of linear relationship, i.e., all proportional relationships are linear relationships (although not all linear relationships are proportional).

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3 years ago
SOLUTION We observe that f '(x) = -1 / (1 + x2) and find the required series by integrating the power series for -1 / (1 + x2).
Ann [662]

Answer:

Required series is:

\int{\frac{-1}{1+x^{2}} \, dx =-x+\frac{x^{3}}{3}-\frac{x^{5}}{5}+\frac{x^{7}}{7}+.....

Step-by-step explanation:

Given that

                           f'(x) = -\frac{1}{1 + x^{2}} ---(1)

We know that:

                  \frac{d}{dx}(tan^{-1}x)=\frac{1}{1+x^{2}} ---(2)

Comparing (1) and (2)

                           f'(x)=-(tan^{-1}x) ---- (3)

Using power series expansion for tan^{-1}x

f'(x)=-tan^{-1}x=-\int {\frac{1}{1+x^{2}} \, dx

= -\int{ \sum\limits^{ \infty}_{n=0} (-1)^{n}x^{2n}} \, dx

= -\sum{ \int\limits^{ \infty}_{n=0} (-1)^{n}x^{2n}} \, dx

=-[c+\sum\limits^{ \infty}_{n=0} (-1)^{n}\frac{x^{2n+1}}{2n+1}]

=C+\sum\limits^{ \infty}_{n=0} (-1)^{n+1}\frac{x^{2n+1}}{2n+1}

=C-x+\frac{x^{3}}{3}-\frac{x^{5}}{5}+\frac{x^{7}}{7}+.....

as

                 tan^{-1}(0)=0 \implies C=0

Hence,

\int{\frac{-1}{1+x^{2}} \, dx =-x+\frac{x^{3}}{3}-\frac{x^{5}}{5}+\frac{x^{7}}{7}+.....

7 0
3 years ago
Which two triangles are congruent? Complete the congruence statement.
shtirl [24]

Answer:

tsu and hgi

Step-by-step explanation:

8 0
3 years ago
A missing fraction on a number line is located exacly halfway between 3/6 and 5/6. What is the missing fraction?
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The missing number would be 4/6, or 2/3.

The missing number can be found by finding the absolute distance in between the numbers, dividing it and then adding it to the smaller number.

(5/6-3/6)/2=(2/6)/2=1/6
3/6+1/6=4/6 or 2/3

8 0
2 years ago
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