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kenny6666 [7]
3 years ago
12

How do you find the range in a set of numbers?

Mathematics
2 answers:
Angelina_Jolie [31]3 years ago
7 0

Answer:

first order the data from least to greatest. Then subtract the smallest value from the largest value in the set

Step-by-step explanation:

sukhopar [10]3 years ago
5 0

Answer: the range is the difference between the largest number and the lowest number

Step-by-step explanation: subtract the largest number from the lowest number

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Are lines of symmetry also diagonals in a polygon? Explain.
Vaselesa [24]
Well not all lines are lines of symmerty, because if you draw a let's say a rectangle on a piece of paper and draw a diagonal line through it, well the two sides don't really lie perfectly on one another!!
3 0
3 years ago
Evaluate the expression (-3) 3
denis-greek [22]

Answer:

-9

Step-by-step explanation:

This is just -3 * 3

=-9

6 0
1 year ago
Read 2 more answers
(7-4) + 17 / -14 + 2 x 5
Yuliya22 [10]

Answer:

165/14

Step-by-step explanation:

(7-4) + 17 / -14 + 2 x 5

3 + 17/-14 + 2 x 5

3 - 17/14 + 2 x 5

3 - 17/14 + 10

165/14

8 0
3 years ago
(b) dy/dx = (x - y+ 1)^2
Elanso [62]

Substitute v(x)=x-y(x)+1, so that

\dfrac{\mathrm dv}{\mathrm dx}=1-\dfrac{\mathrm dy}{\mathrm dx}

Then the resulting ODE in v(x) is separable, with

1-\dfrac{\mathrm dv}{\mathrm dx}=v^2\implies\dfrac{\mathrm dv}{1-v^2}=\mathrm dx

On the left, we can split into partial fractions:

\dfrac12\left(\dfrac1{1-v}+\dfrac1{1+v}\right)\mathrm dv=\mathrm dx

Integrating both sides gives

\dfrac{\ln|1-v|+\ln|1+v|}2=x+C

\dfrac12\ln|1-v^2|=x+C

1-v^2=e^{2x+C}

v=\pm\sqrt{1-Ce^{2x}}

Now solve for y(x):

x-y+1=\pm\sqrt{1-Ce^{2x}}

\boxed{y=x+1\pm\sqrt{1-Ce^{2x}}}

3 0
3 years ago
Which function describes the arithmetic sequence shown<br><br> -1, 1, 3, 5, 7, 9, 11, 13, ...
riadik2000 [5.3K]

Answer:

f(n) = 2n - 3 describes the arithmetic sequence,

-1, 1, 3, 5, 7, 9, 11, 13,.......

Step-by-step explanation:

Function:

A function is like a machine that gives an output for a given input.

A function has an independent variable which is called the input of the function.

The output for a given input is called the dependent variable.

Here. 'n' is the independent variable

f(n) is the function dependent variable i.e function of n as an output.

For Arithmetic sequence

a_{n}= a_{1} + (n-1)d

Where

a_{n} = nth number of the sequence.

a₁ = First term

d = common difference = a₂ - a₁ = a₃ - a₂ = so on

For a function which describes Arithmetic sequence,

a₁ = -1

d = 1 - -1 =2

∴ f(n) = a₁ + (n -1 )d

substituting the values we get

∴ f(n) = -1 +(n-1)2

using distributive property

∴ f(n) = - 1 +  2n - 2

∴ f(n) = 2n - 3  ..........is the required function

7 0
3 years ago
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