Answer:
D (the last one)
Step-by-step explanation:
-x would equal 0 on the x axis and -4 would be plotted at -4 on the y axis
Answer:
Doesn't fit
Step-by-step explanation:
There are 2.4litres in the beaker if you count the lines; they increment by 0.4 litres each. The volume of the storage container is 20 x 15 x 7 = 2100 cm^3 (cm cubed). 1 cm^3 = 1 ml; the cube can hold 2100 mL which is 2.1 litres, which is less than the 2.4 litres in the beaker, therefore it will not fit.
Step-by-step explanation:
8|x+2|-6=5|x+2|+3
|8x+16|-6=|5x+10|+3
I've been thinking... Is that | or (? Are you sure it's |?
Oh well, I'm continuing...
8x+16-6=5x+10+3
8x+10=5x+13
3x=3
x=1
Answers:
- Discrete
- Continuous
- Discrete
- Continuous
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Explanations:
- This is discrete because we can't have half a basketball, or any non-whole decimal value to represent the number of basketballs. We can only consider positive whole numbers {1,2,3,4,...}. A discrete set like this has gaps between items. In other words, the midpoint of 2 and 3 (the value 2.5) isn't a valid number of basketballs.
- This is continuous because time values are continuous. We can take any two different markers in time, and find a midpoint between them. For example, the midpoint of 5 minutes and 17 minutes is 11 minutes since (5+17)/2 = 22/2 = 11. Continuous sets like this do not have any gaps between items. We can consider this to be densely packed.
- This is the same as problem 1, so we have another discrete function. You either score a bullseye or you don't. We can't score half a bullseye. The only possible values are {1,2,3,4,...}
- This is similar to problem 2. This function is continuous. Pick any two different positive real numbers to represent the amount of gallons of water. You will always be able to find a midpoint between those values (eg: we can have half a gallon) and such a measurement makes sense.
So in short, always try to ask the question: Can I pick two different values, compute the midpoint, and have that midpoint make sense? If so, then you're dealing with a continuous variable. Otherwise, the data is discrete.
34 and 38 are both multiples of 34 and 38 so divide each by 2
34/38 = 17/19
this is its simplest form as it cannot be cancelled down any more
