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BARSIC [14]
3 years ago
12

The output of a function is 5 more than -2 times the input. Write and solve an equation to find the input when the output is 11

Mathematics
1 answer:
Law Incorporation [45]3 years ago
7 0

Answer:

17 is x=6.

Step-by-step explanation:k

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CANT GET WRONG
Allushta [10]
The correct answer would be D. because if the equation has a y-intercept (+4) than the line doesn't go through the origin.
6 0
3 years ago
Read 2 more answers
Can someone please teach me how to add, subtract, multiply and divide negative numbers?
dedylja [7]
If both numbers are negative u add those up and ur answer will be a negative. so number one is negative 9.
if there is more positive ur answer will be a positive. so number 2 is 13.
number is more complicated so negative 3 +4 is 1 because u have more positive and u just subtract those then 1 minus 8 equals negative 7 and negative 7 minus 7 is 0. hope this helps
3 0
3 years ago
Read 2 more answers
I need help anyone know
kaheart [24]

Answer:

yes ur correct its nonlinear lol

Step-by-step explanation:

6 0
3 years ago
For the given function, x can have what value?
Lyrx [107]

Answer:

x cannot be -4,-3, or 13

x can be anything else

Step-by-step explanation:

There are infinitely many values x can take where the relation above will be a function.

For it to be a function, you just need to make sure each x is only assigned one y value.

So x couldn't be -4 because it would by assigned to y=2 and y=0.

x couldn't be -3 because it would be assigned to y=1 and y=0.

x couldn't be 13 because it would be assigned to y=5 and y=0.

So as long as x is not chosen to be -4,-3, or 13 your relation here is a function.

5 0
3 years ago
Explain how to evaluate simplify and convert to radical form (x^3/8)^3/4
Vaselesa [24]

Answer:

(x^\frac{3}{8})^\frac{3}{4}  = \sqrt[32]{x^9}

Step-by-step explanation:

Given

(x^\frac{3}{8})^\frac{3}{4}

Required

Convert to radical form

(x^\frac{3}{8})^\frac{3}{4}

Evaluate the exponents

(x^\frac{3}{8})^\frac{3}{4} = x^\frac{3*3}{8*4}

(x^\frac{3}{8})^\frac{3}{4} = x^\frac{9}{32}

Split the exponent

(x^\frac{3}{8})^\frac{3}{4} = (x^9)^\frac{1}{32}

Apply the following law of indices

(x^a)^\frac{1}{b} = \sqrt[b]{x^a}

So, we have:

(x^\frac{3}{8})^\frac{3}{4}  = \sqrt[32]{x^9}

3 0
3 years ago
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