The correct answer would be D. because if the equation has a y-intercept (+4) than the line doesn't go through the origin.
If both numbers are negative u add those up and ur answer will be a negative. so number one is negative 9.
if there is more positive ur answer will be a positive. so number 2 is 13.
number is more complicated so negative 3 +4 is 1 because u have more positive and u just subtract those then 1 minus 8 equals negative 7 and negative 7 minus 7 is 0. hope this helps
Answer:
yes ur correct its nonlinear lol
Step-by-step explanation:
Answer:
x cannot be -4,-3, or 13
x can be anything else
Step-by-step explanation:
There are infinitely many values x can take where the relation above will be a function.
For it to be a function, you just need to make sure each x is only assigned one y value.
So x couldn't be -4 because it would by assigned to y=2 and y=0.
x couldn't be -3 because it would be assigned to y=1 and y=0.
x couldn't be 13 because it would be assigned to y=5 and y=0.
So as long as x is not chosen to be -4,-3, or 13 your relation here is a function.
Answer:
![(x^\frac{3}{8})^\frac{3}{4} = \sqrt[32]{x^9}](https://tex.z-dn.net/?f=%28x%5E%5Cfrac%7B3%7D%7B8%7D%29%5E%5Cfrac%7B3%7D%7B4%7D%20%20%3D%20%5Csqrt%5B32%5D%7Bx%5E9%7D)
Step-by-step explanation:
Given

Required
Convert to radical form

Evaluate the exponents


Split the exponent

Apply the following law of indices
![(x^a)^\frac{1}{b} = \sqrt[b]{x^a}](https://tex.z-dn.net/?f=%28x%5Ea%29%5E%5Cfrac%7B1%7D%7Bb%7D%20%3D%20%5Csqrt%5Bb%5D%7Bx%5Ea%7D)
So, we have:
![(x^\frac{3}{8})^\frac{3}{4} = \sqrt[32]{x^9}](https://tex.z-dn.net/?f=%28x%5E%5Cfrac%7B3%7D%7B8%7D%29%5E%5Cfrac%7B3%7D%7B4%7D%20%20%3D%20%5Csqrt%5B32%5D%7Bx%5E9%7D)