Answer:
Area of the sector = 57.26295cm²
Step-by-step explanation:
Radius of the circle=9cm
π= 3.142
Angle at B= 81° ( opposite angle of a quadrilateral)
Area of the sector = πr² * 81/360
Area of the sector = 3.142 * 9*9 * 0.225
Area of the sector= 3.142*81*0.225
Area of the sector = 57.26295cm²
Answer:
Okay so what you are looking at is a triangle with a cross section. That is line segment PQ.You ae asked to find the length of PN. What you are given is the height(s) of NQ (5 units), QM (2 units) and PL (3 units). You can make an educated guess that line NP equals 4 units. Mainly because those two little arrows on lines LM and PQ (that means that the two lines are parallel). hope it helps...
1) Use the pathagreom theorem; a^2+b^2=c^2
(The hypotenuse is always c. The other two legs can be either a or b.)
*use x for the unknown side*
1. Plug in the measurements
4^2+x^2=8.5^2
2. Solve
16+x^2=72.25
RADICAL(56.25)=> 7.5
The measure of the other side of the triangle (x) is= 7.5 m
2) Draw a square with the measure of 20 cm on each side.
Draw a diagonal line across the square.
(Use the pathagroeam theorem)
We know that the legs are 20, and 20. The hypotenuse is what we are trying to find (x).
1. Plug in the measurements
20^2+20^2=x^2
2. Solve
800= x^2
20 RADICAL(2)=> 28.28
The measure of the other side of the triangle (x) is= 28.3 cm
Answer:
2,550
Step-by-step explanation:
you are going to add 1,500 + 1,000 + 1,200 = 3,700 then you are going to subtract 6,250-3,700 = 2,550 and that is the answer
