The answer would be x = -3
Answer:
Step-by-step explanation:
See the figure below.
This is how you graph directly from the equation in the slope-intercept form (y = mx + b) without having to create a table of x and y values.
The equation is
y = -2/3 x + 1
Compare it with
y = mx + b
b = 1
The y-intercept is 1, so mark 1 on the y-axis. (You already did.)
I placed a black dot there.
The slope is m.
m = -2/3
slope = m = rise/run
A slope of -2/3 can be though of as -2 rise and 3 run. That means start from the y-intercept, and go -2 in y (a rise of 2 down) and 3 in x (a run 3 right). Point graphed in red.
Mathematically, -2/3 is the same as 2/(-3), so starting again from the y-intercept, this slope can also be though of as rise of 2 in y (a rise of 2 up) and a run of -3 in x (a run of 3 left). Point graphed in green.
The line is graphed in blue.
Answer:
sin(θ) = 12/13, cos(θ) = 5/13, tan(θ) = 12/5
Step-by-step explanation:
We need to find sine, cosine, and tangent of theta for this triangle.
First, define the different trigonometric functions:
- sine is opposite side to the angle divided by the hypotenuse (longest side not adjacent to the 90 degree angle)
- cosine is the adjacent side next to the angle divided by the hypotenuse
- tangent is the opposite side to the angle divided by the adjacent side
Now, look at theta (θ):
- the opposite side is marked 12
- the adjacent side is marked 5
- the hypotenuse is marked 13
So:
- sin(θ) = opposite / hypotenuse = 12/13
- cos(θ) = adjacent / hypotenuse = 5/13
- tan(θ) = opposite / adjacent = 12/5
Thus the answers are: sin(θ) = 12/13, cos(θ) = 5/13, tan(θ) = 12/5.
Your answer will be 6. The reason it is six is that 24/6 = 4 and 4 X 6=24.
line segment connecting the vertices of a hyperbola is called the <u>transverse axis</u> and the midpoint of the line segment is the <u>center</u> of the hyperbola.
What is transverse axis and center of hyperbola ?
The transverse axis is a line segment that passes through the center of the hyperbola and has vertices as its endpoints. The foci lie on the line that contains the transverse axis. The conjugate axis is perpendicular to the transverse axis and has the co-vertices as its endpoints.
And The center of a hyperbola is the midpoint of both the transverse and conjugate axes, where they intersect. Every hyperbola also has two asymptotes that pass through its center. As a hyperbola recedes from the center, its branches approach these asymptotes.
Learn more about the transverse axis and center of hyperbola here:
brainly.com/question/28049753
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