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nata0808 [166]
3 years ago
7

What is the next number in this pattern? 0, 3, 15, 63

Mathematics
1 answer:
Over [174]3 years ago
6 0
The next number is 255.
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he entry fee to the fair is 4.00 . each rides requires a ticket that cost 0.50 heidi spent a total 12.00 how many ticket did hei
elixir [45]
Hey there!

Set up an equation. This would be 4+0.5x=12. You have to get x by itself, so subtract 4 on each side. You get 0.5x=8. Divide by 0.5 on each side to get x=16. Heidi purchased 16 tickets.

I hope this helps!
6 0
4 years ago
What is the third angle of a right triangle if one of the angles measures 42.6
Llana [10]

Answer:

112

Step-by-step explanation:

lol not 100% sure

5 0
3 years ago
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How to factor the polynomial completly​
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5 0
3 years ago
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We need a rock garden with a perimeter of 12 feet and an area of 8 square feet what is the length and width
Katarina [22]

The dimensions of the rectangle can be a length of 2ft and a width of 4ft.

<h3>How to find the dimensions of the garden?</h3>

Remember that for a rectangle of length L and width W, the perimeter is:

P = 2*(L + W)

And the area is:

A = L*W

In this case, we know that the area is 8 square feet and the perimeter is 12 ft, then we have a system of equations:

12ft = 2*(L + W)

8ft² = L*W

To solve this, we first need to isolate one of the variables in one of the equations, I will isolate L on the first one:

12ft/2 = L + W

6ft - W = L

Now we can replace that in the other equation to get:

8ft² = (6ft - W)*W

This is a quadratic equation:

-W^2 + 6ft*W - 8ft² = 0

The solutions are given by Bhaskara's formula:

W = \frac{-6 \pm \sqrt{(6ft)^2 - 4*(-1)*(-8)} }{2*-1} \\\\W = \frac{-6 \pm 2}{-2}

Then we have two solutions:

W = (-6 - 2)/-2 = 4ft

W = (-6 + 2)/-2 = 2ft

If we take any of these solutions, the length will be equal to the other solution.

So the dimensions of the rectangle can be a length of 2ft and a width of 4ft.

if you want to learn more about rectangles:

brainly.com/question/17297081

#SPJ1

4 0
3 years ago
NEED HELP Find values for a, b, c, and d so that the following matrix product equals the 2X2 identity matrix. Explain or show ho
ehidna [41]

We want to find the values of a, b, c, and d such that the given matrix product is equal to a 2x2 identity matrix. We will solve a system of equations to find:

  • b = 1
  • a = -1
  • c = -2
  • d = -1

<h3>Presenting the equation:</h3>

Basically, we want to solve:

\left[\begin{array}{cc}-1&2\\a&1\end{array}\right]*\left[\begin{array}{cc}b&c\\1&d\end{array}\right] = \left[\begin{array}{cc}1&0\\0&1\end{array}\right]

The matrix product will be:

\left[\begin{array}{cc}-b + 2&-c + 2d\\a*b + 1&a*c + d\end{array}\right]

Then we must have:

-b + 2 = 1

This means that:

b = 2 - 1 = 1

  • b = 1

We also need to have:

a*b + 1 = 0

we know the value of b, so we just have:

a*1 + b = 0

  • a = -1

Now the two remaining equations are:

-c + 2d = 0

a*c + d = 1

Replacing the value of a we get:

-c + 2d = 0

-c + d = 1

Isolating c in the first equation we get:

c = 2d

Replacing that in the other equation we get:

-(2d) + d = 1

-d = 1

  • d = -1

Then:

c  = 2d = 2*(-1) = -2

  • c = -2

So the values are:

  • b = 1
  • a = -1
  • c = -2
  • d = -1

If you want to learn more about systems of equations, you can read:

brainly.com/question/13729904

4 0
3 years ago
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