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2 years ago

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Mathematics

1 answer:

zhannawk [14.2K]2 years ago

5 0

Answer:

Step-by-step explanation:

The question is a little vague, but I’m assuming you meant to say x + y. If that’s the case just do 24 + 17, which is 41.

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Can someone please help me this? Math 8

Viefleur [7K]

Answer:

$5x + ( - 8)x + 9 + ( - 4) \\ 5x - 8x + 9 - 4 \\ - 3x + 5$

this is the solution

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3 years ago

Consider this three-digit sequence: 943. Is the first digit the largest or the second digit the smallest, AND, is the third digi

Delicious77 [7]

your question isn't very clear, but I'll try to answer

943
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3 years ago

equation 7(2j + 3 + 2j). use mathematical properties to create two expressions that are equivalent to the expression you created

makvit [3.9K]

Answer:

Step-by-step explanation:

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2 years ago

If 180° < α < 270°, cos⁡ α = −817, 270° < β < 360°, and sin⁡ β = −45, what is cos⁡ (α + β)?

eduard

Answer:

$cos(\alpha+\beta)=-\frac{84}{85}$

Step-by-step explanation:

we know that

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

Remember the identity

$cos^{2} (x)+sin^2(x)=1$

step 1

Find the value of $sin(\alpha)$

we have that

The angle alpha lie on the III Quadrant

The values of sine and cosine are negative

$cos(\alpha)=-\frac{8}{17}$

Find the value of sine

$cos^{2} (\alpha)+sin^2(\alpha)=1$

substitute

$(-\frac{8}{17})^{2}+sin^2(\alpha)=1$

$sin^2(\alpha)=1-\frac{64}{289}$

$sin^2(\alpha)=\frac{225}{289}$

$sin(\alpha)=-\frac{15}{17}$

step 2

Find the value of $cos(\beta)$

we have that

The angle beta lie on the IV Quadrant

The value of the cosine is positive and the value of the sine is negative

$sin(\beta)=-\frac{4}{5}$

Find the value of cosine

$cos^{2} (\beta)+sin^2(\beta)=1$

substitute

$(-\frac{4}{5})^{2}+cos^2(\beta)=1$

$cos^2(\beta)=1-\frac{16}{25}$

$cos^2(\beta)=\frac{9}{25}$

$cos(\beta)=\frac{3}{5}$

step 3

Find cos⁡ (α + β)

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

we have

$cos(\alpha)=-\frac{8}{17}$

$sin(\alpha)=-\frac{15}{17}$

$sin(\beta)=-\frac{4}{5}$

$cos(\beta)=\frac{3}{5}$

substitute

$cos(\alpha+\beta)=-\frac{8}{17}*\frac{3}{5}-(-\frac{15}{17})*(-\frac{4}{5})$

$cos(\alpha+\beta)=-\frac{24}{85}-\frac{60}{85}$

$cos(\alpha+\beta)=-\frac{84}{85}$

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3 years ago

Which statement is true about the measure of angle R’??

aleksley [76]

Answer:

Angle R is an Angle

Step-by-step explanation:

This question has no photo or context

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3 years ago