I = PRT
21 = 200 * 0.035 * T
21 = 7T
3 years = T
9514 1404 393
Answer:
Step-by-step explanation:
In the left problem, you use the fact that <em>the sum of the segment lengths is equal to the overall length</em>.
AC +CB = AB
(3x -4) +(x -2) = 62
4x -6 = 62 . . . . . collect terms
4x = 68 . . . . . . . add 6
x = 17 . . . . . . . . . . divide by 4
__
In the right problem, you use the fact that <em>the sum of the angles is equal to the overall angle</em>. Here, that overall angle is a linear angle, so measures 180°.
∠DFG +∠GFE = ∠DFE
(5y +3) +(2y -5) = 180
7y = 182 . . . . . . . . . . . . . . collect terms, add 2
y = 26 . . . . . . . . . . . . . . . .divide by 7
Answer:
I believe it would be 18.568 or round up to 18
Step-by-step explanation:
B. because when you multiply the factors they will get B
Mass of freight train: 9.98 • 106
= 1057.88 kg
mass of aircraft carrier: 7.3 • 107
= 781.1 kg
difference: 1057.88 - 781.1
= 276.78 kg
= 2.7678 x 10^2
