What the value of k makes the equation true ? 4/k = 2/3

Given ∆ABC≅∆PQR, mb=8v-9 , find m 31° b. 52° c. 49° d. 32°

Ipatiy [6.2K]

Here, 5v+6 = 8v-9
8v - 5v = 6 + 9
3v = 15
v = 15/3
v = 5

So, m<b = 5(5) + 6 = 25 + 6 = 31
As they are congruent, m<q would be same [ 31 degree ]

In short, Your Answer would be Option A

Hope this helps!

3 0

3 years ago

A questionnaire has determined that 20% of the residents of Flaugamuck County own an iPod. Furthermore, 80% of these iPod owners

nydimaria [60]

Answer:

P = 7.14%

The percentage of those 30 years or older that own an ipod is 7.14%

Step-by-step explanation:

Given;

Percentage of ipod owners Pi = 20%

Percentage who don't own ipod Pd = 100-20 = 80%

For age 30 or older;

Percentage of ipod owners who belong to this group

Po = 20% of Pi

Percentage who don't have an ipod but belong to this group Pu = 100-35% = 65% of Pd

The percentage of those 30 years or older that own an ipod is;

P = Po/(Po+Pu) × 100%

Po = 20% of Pi = 20% of 20% = 0.2×20 =4%

Pu = 65% of Pd = 65% of 80% = 0.65×80% = 52%

Substituting the values;

P = 4/(4+52) × 100%

P = 7.14%

5 0

3 years ago

According to a recent survey, the population distribution of number of years of education for self-employed individuals in a c

creativ13 [48]

Answer:

a) X: number of years of education

b) Sample mean = 13.5, Sample standard deviation = 0.4

c) Sample mean = 13.5, Sample standard deviation = 0.2

d) Decrease the sample standard deviation

Step-by-step explanation:

We are given the following in the question:

Mean, μ = 13.5 years

Standard deviation,σ = 2.8 years

a) random variable X

X: number of years of education

Central limit theorem:

If large random samples are drawn from population with mean $\mu$ and standard deviation $\sigma$ , then the distribution of sample mean will be normally distributed with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$

b) mean and the standard for a random sample of size 49

$\mu_{\bar{x}} = \mu = 13.5\\\\\sigma_{\bar{x}} = \dfrac{\sigma}{\sqrt{n}} = \dfrac{2.8}{\sqrt{49}} = 0.4$

c) mean and the standard for a random sample of size 196

$\mu_{\bar{x}} = \mu = 13.5\\\\\sigma_{\bar{x}} = \dfrac{\sigma}{\sqrt{n}} = \dfrac{2.8}{\sqrt{196}} = 0.2$

d) Effect of increasing n

As the sample size increases, the standard error that is the sample standard deviation decreases. Thus, quadrupling sample size will half the standard deviation.

7 0

3 years ago

Find the 17th term of the arithmetic sequence -5, 1, 7, 13, ... *

xz_007 [3.2K]

Answer:

91

Step-by-step explanation:-5, 1, 7, 13

the common diference is : d = ( 13)-(7)=(7)-(1)=(1)-(-5)=6

the firt term is A1 = -5

the n-ieme term is : An = A1 +(n-1)d

An = -5+6(n-1)

An = 6n-11

the 17th term in the arithmetic sequence is : A17 = 6(17)-11 =91

Read more on Brainly.com - brainly.com/question/15374982#readmore

7 0

4 years ago

I need help on this! It is on Big Ideas Math.

Anastaziya [24]

Segment AB is opposite segment CD in the figure, thus they are parallel from each other. Segment AB, as indicated by its name, contains point B.

So, the correct answer is segment AB.

4 0

1 year ago