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2 years ago

Plz help I really need it and you get 15 points

Mathematics

1 answer:

Andrei [34K]2 years ago

8 0

1. 1 x-200= -200
2. -200 x 1= -200
3. 2 x -100= -200
4. -100 x 2= -200
5. -20 x 10= -200
6. -10 x 20= -200
7. -40 x 5= -200
8. -5 x 40= -200
Hope this helps! :)

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Solve the system x - 2y = -6 3x + y = -4

stepan [7]

{x-2y=-6

{3x+y=-4 /*2

{x-2y=-6

{6x+2y=-8 (+)

7x=-14 /:7

x=-2

3x+y=-4

3*(-2)+y=-4

-6+y=-4

y=2

Solution: (-2; 2)

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3 years ago

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Answer:

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3 years ago

Piano lessons cost $15. What expressions could be used to find the cost in dollars of 5 lessons

kirill115 [55]

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3 years ago

What is the value of log 7 343?–3 -1/3 1/3 3

xeze [42]

Answer: 3

Step-by-step explanation:

Given :

$Log_{7}$ 343

We need to write 343 in index form of 7.

343 is the same as $7^{3}$ , replacing 343 with $7^{3}$ , we have

$Log_{7}$ $7^{3}$

Recall one on the law of Logarithm :

$Log_{a}$ $b^{c}$ can be written as c $Log_{a}$ b

So, $Log_{7}$ $7^{3}$ can be written as ;

3 $Log_{7}$ 7

Also from the laws of Logarithms , $Log_{a}$ a = 1

so , Log_{7}[/tex] 7 = 1

The solution then becomes

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Therefore :

$Log_{7}$ 343 = 3

8 0

3 years ago

Please help with 3. 4. 5.

Eddi Din [679]

3.
$\text{The Triangle Sum Theorem:}\\m\angle A+m\angle B+m\angle C=180^o$
$x+2x-1+3x+1=180\\6x=180\ \ \ |:6\\x=30$
$x^o=30^o\\(3x+1)^o=(3\cdot30+1)^o=91^o\\(2x-1)^o=(2\cdot30-1)^o=59^o$
4.
$r-6+3r-3+5r=180\\9r-9=180\ \ \ |+9\\9r=189\ \ \ |:9\\r=21$
$(r-6)^o=(21-6)^o=15^o\\(3r-3)^o=(3\cdot21-3)^o=60^o\\(5r)^o=(5\cdot21)^o=105^o$
5.
$\text{The Exterior Angle Theorem:}\\m\angle CAB+m\angle ABC=m\angle DCB$
$2g+9g=110\\11g=110\ \ \ |:11\\g=10$
$m\angle A=2\cdot10^o=20^o\\m\angle ACB=180^o-110^o=70^o\\m\angle B=9\cdot10^o=90^o$

4 0

3 years ago