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mojhsa [17]
3 years ago
14

What is 265,409 rounded to the nearest hundred thousand

Mathematics
2 answers:
sweet-ann [11.9K]3 years ago
6 0
The Answer Is 300,000 
Ne4ueva [31]3 years ago
4 0
Your answer would be 300,000
5 or higher will round up!
You might be interested in
Divide -6/7 by 2/-3 please give answer very fast its urgent
defon

Answer:

0.14285714285

Step-by-step explanation:

divide on calculator and make sure to have negative sign before three, remember you are dividing fractions

I hope it helps! If not sorry :(

3 0
3 years ago
Read 2 more answers
How do you do the last two questions?
Mashutka [201]

Answer:

P = 6200 / (1 + 5.2e^(0.0013t))

increases the fastest

Step-by-step explanation:

dP/dt = 0.0013 P (1 − P/6200)

Separate the variables.

dP / [P (1 − P/6200)] = 0.0013 dt

Multiply the left side by 6200 / 6200.

6200 dP / [P (6200 − P)] = 0.0013 dt

Factor P from the denominator.

6200 dP / [P² (6200/P − 1)] = 0.0013 dt

(6200/P²) dP / (6200/P − 1) = 0.0013 dt

Integrate.

ln│6200/P − 1│= 0.0013t + C

Solve for P.

6200/P − 1 = Ce^(0.0013t)

6200/P = 1 + Ce^(0.0013t)

P = 6200 / (1 + Ce^(0.0013t))

At t = 0, P = 1000.

1000 = 6200 / (1 + C)

1 + C = 6.2

C = 5.2

P = 6200 / (1 + 5.2e^(0.0013t))

You need to change the exponent from negative to positive.

The inflection points are where the population increases the fastest.

5 0
3 years ago
11. The news reports that today's high temperature is 16°F colder than
LenaWriter [7]

Answer:

2x3+6x2/5x3 thats the expression

Step-by-step explanation:

3 0
2 years ago
In 2000, there were 12900 students at college A, with a projected enrollment increase of 900 students per year. In the same year
LenaWriter [7]

Answer:

Step-by-step explanation:

Let x represent the number of years it will take the two colleges to have the same enrollment.

In 2000, there were 12900 students at college A, with a projected enrollment increase of 900 students per year. This means that the expected number of students at college A in x years time is

12900 + 900x

In the same year, there were 25,000 students at college B, with a projected enrollment decline of 700 students per year. This means that the expected number of students at college B in x years time is

25000 - 700x

For both colleges to have the same enrollment,

12900 + 900x = 25000 - 700x

900x + 700x = 25000 - 12900

1600x = 12100

x = 12100/1600

x = 7.56

Approximately 8 years

The year would be 2000 + 8 = 2008

4 0
3 years ago
PLEASE HELP!!!! WILL GIVE BRAINLIEST!!!!!!!
azamat

f(x) = 0.5x   -   money per ticket

g(x) = 8x   -   tickets per hour

We replace g(x) with its value (8x).

f(g(x)) = f(8x)

We replace the x in f(x) with 8x.

f(8x) = 0,5 × 8x

f(8x) = 4x

<u>⇒ f(g(x)) = 4x</u>

<u></u>

Correct answer:

a.<em> f(g(x)) = 4x, which represents the money Aurora made in dollars per hour</em>

7 0
3 years ago
Read 2 more answers
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