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podryga [215]
3 years ago
5

Suppose that weights of bags of potato chips coming from a factory follow a normal distribution with mean 12.8 ounces and standa

rd deviation 0.6 ounces. A bag of chips is taken off the conveyor belt and weighed. If the weight found was 12.55 ounces, then what is the corresponding z-score for that data?
Round your answer to two decimal places.
Mathematics
1 answer:
alisha [4.7K]3 years ago
4 0

Answer:

std dev = 0.625

Given that  weights of bags of potato chips coming from a factory follow a normal distribution with mean 12.8 ounces and standard deviation .6 ounces.

We must change std deviation such that

P(X<12) =0.01

Mean would remain the same as 12.8 oz

From normal distribution score we can find

10th percentile is -1.28\

i.e. we must have

Std deviation should be 0.625

Step-by-step explanation:

Hope this helps:)

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A candy store called "Sugar" built a giant hollow sugar cube out of wood to hang above the entrance to their store. It took 5454
Elina [12.6K]

Answer:

27 ft^3

Step-by-step explanation:

The total surface area of the cube is 54 ft^2.

A cube has 6 congruent square sides.

54 ft^2/5 = 9 ft^2

Each square side has area 9 ft^2.

The area of a square is the square of the side, so the side of a square is the square root of the area.

side = sqrt(9 ft)^2 = 3 ft

The volume of a cube is the cube of the side.

volume = (3 ft)^3

volume = 27 ft^3

4 0
3 years ago
What is the value of x in the equation 2(x+3) = 4(x-1)?<br> own
11111nata11111 [884]

Step-by-step explanation:

Solving

2x + 6 = 4x - 4

Bringing like terms on one side

6 + 4 = 4x - 2x

10 = 2x

10 / 2 = x

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8 0
3 years ago
What is the standard form of the equation of a line for which the length of the normal segment to the origin is 8 and the normal
jeka57 [31]
Slope of line = tan(120) = -tan(60) = - &radic;3
Distance from origin = 8

Let equation be Ax+By+C=0
then -A/B=-&radic;3, or
B=A/&radic;3.
Equation becomes
Ax+(A/&radic;3)y+C=0

Knowing that line is 8 units from origin, apply distance formula
8=abs((Ax+(A/&radic;3)y+C)/sqrt(A^2+(A/&radic;3)^2))
Substitute coordinates of origin (x,y)=(0,0)  =>
8=abs(C/sqrt(A^2+A^2/3))
Let A=1 (or any other arbitrary finite value)
solve for positive solution of C
8=C/&radic;(4/3) => C=8*2/&radic;3 = (16/3)&radic;3

Therefore one solution is
x+(1/&radic;3)+(16/3)&radic;3=0
or equivalently
&radic;3 x + y + 16 = 0

Check:
slope = -1/&radic;3  .....ok
distance from origin
= (&radic;3 * 0 + 0 + 16)/(sqrt(&radic;3)^2+1^2)
=16/2
=8  ok.

Similarly C=-16 will satisfy the given conditions.

Answer  The required equations are
&radic;3 x + y = &pm; 16 
in standard form.

You can conveniently convert to point-slope form if you wish.




4 0
4 years ago
W h a t is the meaning of life?
Elina [12.6K]

Answer:

50% increase

Step-by-step explanation:

please award brainiest thank and rate 5 star

8 0
3 years ago
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Please hellppp i will mark brainliest ​
castortr0y [4]
30 degrees it's right
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