The length and width that will maximize the area are 175 ft and 87.5 ft respectively
The largest area that can be enclosed is 15312.5 ft²
<h3>Area of a rectangle</h3>
where
l = length
w = width
The fencing is 350 ft it is use to enclose a rectangular plot with a river occupying one part.
Therefore,
perimeter = l + 2w
350 = l + 2w
l = 350 - 2w
area = (350 - 2w)w
(350 - 2w)w = 0
where
w = 0 or 175
average = 175/2 = 87.5
Hence, the max area is at w = 87.5 ft
Therefore,
l = 350 - 2(87.5) = 175 ft
length = 175 ft
width = 87.5 ft
Therefore,
area = 175 × 87.5 = 15312.5 ft²
Therefore, the largest area that can be enclosed is 15312.5 ft²
learn more on rectangle here: brainly.com/question/11630499
Answer:
D. Chi-square test for two-way table
Step-by-step explanation:
To test if there is an association between the percentage of people that successfully stop smoking and the method they used to do so, a random sample of 584 smokers who tried to quit smoking and was orted by the method they used to help themselves to achieve their goal (nicotine-patch or e-cigarettes). After six months, the proportion of subjects that successfully stopped smoking.
In this case, the t-test is not applicable, this statistic is to test the population mean. The variable of the study is the proportion of people that successfully stopped smoking using either method.
To apply Chi-Square tests the condition to be met is that the variable is categorizable and since the data can be organized in a 2x2 table, all expected frequencies should be >5.
The objective of the Goodness-to-fit test is to test if a population follows a certain theoretical model.
In this example, the objective is to compare the proportion of people that successfully quit smoking and the proportion of people that failed by using either method.
(7h)^3
=(7h) (7h) (7h)
=7×7×7×h×h×h
343h^3
I use that example all the time
For each sides of the cube that can be rolled, there are 4 parts that the spinner can land on. So the number of outcomes is 6*4, or 24.
Answer: There is no error the steps of the problem.
The problem is solved correctly step by step. In step 1, the person took the reciprocal of the second fraction and changed to multiplication.
In step 2, the factored the second fraction.
In steps 3 and 4, the cancelled out common factors in the top and bottom correctly.