The answer is; The frequency for allele O = 0.7746 while that of o = 0.2254
Well use the hardy Weinberg equation of a population at equilibrium; p2 + 2pq + q2 = 1
In our case, p2 will be 60/100 = 0.6; therefore p = square-root of 0.6 = 0.7746
Remember also that the frequencies of alleles of the same gene add up to one (1); i.e p + q = 1
Therefore q = 1 – 0.7746 = 0.2254
I believe the image represents the stage "metaphase"
Hope this helps!
Major human processes affecting the water cycle on land. storage of water in reservoirs; groundwater mining; irrigation; urbanization; combustion; deforestation; wetlands