First, let's find the angle of inclination using the tangent function.
sin θ = opposite/hypotenuse = 1 m/2 m
θ = 30°
Assuming the ramp is frictionless, the force balance is:
F = mgsinθ = ma
Cancelling out m,
a = gsinθ = (9.81 m/s²)(sin 30°) = 4.905 m/s²
Using the equation for rectilinear motion at constant acceleration,
x = v₀t + 0.5at²
2 m = (6 m/s)(t) + 0.5(4.905 m/s²)(t²)
Solving for tm
t = 0.297 seconds
Using the equation for acceleration:
a = (v - v₀)/t
4.905 m/s² = (v - 6 m/s)/0.297 s
Solving for v,
v = 7.46 m/s
Answer:
The cell membrane is selectively permeable to ions and organic molecules and controls the movement of substances in and out of cells. The basic function of the cell membrane is to protect the cell from its surroundings. It consists of the phospholipid bilayer with embedded proteins.
Yes, he does have family history of heart disease.
Answer:
The correct answer is tropical rain forests.
Explanation:
The hot and moist biome witnessed close to the equator of the Earth is the tropical rainforest. The largest tropical rainforests in the world are found in Africa, South America, and Southeast Asia. About 60 to 160 inches of rainfall is witnessed in the tropical rainforests throughout the year. Due to this, the leaves of the trees found in the tropical rainforests possess unique features that help them to survive.
The leaves of the trees found in the tropical rainforest possess drip tips that help them to cope with the extreme amount of rainfall that takes place throughout the year. The drip tips help the drop of rains to run off briskly from the surface of the leaves. This adaptation helps the plants in the region to prevent the growth of bacteria and fungus.
Initiation:
In the cytoplasm, protein synthesis is actually initiated by the AUG codon on mRNA. The AUG codon signals both the interaction of the ribosome with m-RNA and also the tRNA with the anticodons (UAC). The tRNA which initiates the protein synthesis has N-formyl-methionine attached. The formyl group is really formic acid converted to an amide using the -NH2 group on methionine (left most graphic)
The next step is for a second tRNA to approach the mRNA (codon - CCG). This is the code for proline. The anticodon of the proline tRNA which reads this is GGC. The final process is to start growing peptide chain by having amine of proline to bond to the carboxyl acid group of methinone (met) in order to elongate the peptide.
