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vichka [17]
2 years ago
15

Is 7:21 eqivalent to 2:6

Mathematics
1 answer:
Liono4ka [1.6K]2 years ago
4 0

Answer:

Yes

Step-by-step explanation:

2/6 is equivalent to 7/21 because 1 x 2 = 2 and 3 x 2 = 6

Hope this helps!

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A restaurant owner installed a new automated drink machine. The machine is designed to dispense 530 mLof liquid on the medium si
lidiya [134]

Answer:

a.H0: μ =530mL vs. Ha: μ > 530mL

Step-by-step explanation:

-A hypothesis test will be used to provide evidence that the median is more or equal to the stated median value.

#In a normally distributed population, the mean=mode=median:

Mean=Mode=Median=\mu

-The null hypothesis states that the median is equal to the stated value:

H_o:\mu=530 \ mL

-The alternative hypothesis provides evidence that the median value is greater than the stated value:

H_a:\mu>530\ mL

Hence, the correct hypotheses are H0: μ =530mL vs. Ha: μ > 530mL

6 0
3 years ago
A machine needs 2 of its gears replaced. You find 2 gears, one manufactured 5 years ago and the other manufactured 10 years ago.
Tcecarenko [31]
Probability that gear 1 will fail = 5/100 (upto 10 years) 
and 8/100 (after 10 years)

Probability that both will fail = 5/100 * 8/100
= 40/10000
= 0.4 %

8 0
3 years ago
identify the vertex of the graph tell whether minimum or is it maximum. y equals -1 and xbox equals -4 ​
Kobotan [32]

Answer:

it minimum

Step-by-step explanation:

you didn't really give an equation

3 0
3 years ago
The probability that Aaron goes to the gym on Saturday is 0.8
Ronch [10]

Answer:

The probability that Aaron goes to the gym on exactly one of the two days is 0.74

Step-by-step explanation:

Let P(Aaron goes to the gym on exactly one of the two days) be the probability that Aaron goes to the gym on exactly one of the two days.

Then

P(Aaron goes to the gym on exactly one of the two days) =

P(Aaron goes to the gym on Saturday and doesn't go on Sunday) +

P(Aaron doesn't go to the gym on Saturday and goes on Sunday)

  • If Aaron goes to the gym on Saturday the probability that he goes on Sunday is 0.3. Then If Aaron goes to the gym on Saturday the probability that he does not go on Sunday is 1-0.3 =0.7
  • Since the probability that Aaron goes to the gym on Saturday is 0.8,

P(Aaron goes to the gym on Saturday and doesn't go on Sunday) =

P(the probability that Aaron goes to the gym on Saturday)×P(If Aaron goes to the gym on Saturday the probability that he does not go on Sunday)

=0.8×0.7=0.56

  • The probability that Aaron doesn't go to the gym on Saturday is 1-0.8=0.2
  • And if Aaron does not go to the gym on Saturday the probability he goes on Sunday is 0.9.

Thus, P(Aaron doesn't go to the gym on Saturday and goes on Sunday) = P(The probability that Aaron doesn't go to the gym on Saturday)×P(if Aaron does not go to the gym on Saturday the probability he goes on Sunday)

=0.2×0.9=0.18

Then

P(Aaron goes to the gym on exactly one of the two days) =0.56 + 0.18 =0.74

5 0
2 years ago
Read 2 more answers
I need help with this
Dmitry_Shevchenko [17]

Answer:

14.1 ish

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
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