Identify the figures

Please help ASAP!!!!!<br><br> Answer the question in the image.

Dennis_Churaev [7]

Answer:

151.7

Step-by-step explanation:

You find volume with length times width times height. The length is 3.7. The height is 10 and the width is 4.1. When you multiply together you get 151.7.

5 0

3 years ago

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John wants to buy a DVD player. The price is $100, and the sales tax is 5 percent. Store A is offering a 10 percent discount and

exis [7]

Answer:

Price of DVD at Store A = $ 94.5

Price of DVD at Store B = $ 95

Step-by-step explanation:

Given that

Price of DVD player = $ 100

Sales Tax = 5%

Now, lets calculate price of of DVD player at store A

The price of DVD player at store A after 10% discount = 100 - 10% of 100

The price of DVD player at store A after 10% discount= 100 - 0.1x100

The price of DVD player at store A after 10% discount= 100 - 10 = $90

Price of DVD player at store A after sales tax = 90 + 5% of 90

Price of DVD player at store A after sales tax = 90 + 0.05x90

Price of DVD player at store A after sales tax = 90 + 4.5

Price of DVD player at store A after sales tax = $94.5

Now, lets calculate price of of DVD player at store B.

The price of DVD player at store B= 100

Price of DVD player at store B after sales tax = 100 + 5% of 100

Price of DVD player at store B after sales tax = 100 + 0.05x100

Price of DVD player at store B after sales tax = 100 + 5

Price of DVD player at store B after sales tax = $ 105

Price of DVD player at store B $10 rebate = 105 - 10

Price of DVD player at store B $10 rebate = $95

4 0

3 years ago

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Graph: y-3=1/2 (x+2)

andrey2020 [161]

Here, use the app photomath.

7 0

4 years ago

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Help!! 50 points and brainliest!

Viktor [21]

Answer:

Second choice:

$x=2t$

$y=4t^2+4t-3$

Fifth choice:

$x=t+1$

$y=t^2+4t$

Step-by-step explanation:

Let's look at choice 1.

$x=t+1$

$y=t^2+2t$

I'm going to subtract 1 on both sides for the first equation giving me $x-1=t$ . I will replace the $t$ in the second equation with this substitution from equation 1.

$y=(x-1)^2+2(x-1)$

Expand using the distributive property and the identity $(u+v)^2=u^2+2uv+v^2$ :

$y=(x^2-2x+1)+(2x-2)$

$y=x^2+(-2x+2x)+(1-2)$

$y=x^2+0+-1$

$y=x^2$

So this not the desired result.

Let's look at choice 2.

$x=2t$

$y=4t^2+4t-3$

Solve the first equation for $t$ by dividing both sides by 2:

$t=\frac{x}{2}$ .

Let's plug this into equation 2:

$y=4(\frac{x}{2})^2+4(\frac{x}{2})-3$

$y=4(\frac{x^2}{4})+2x-3$

$y=x^2+2x-3$

This is the desired result.

Choice 3:

$x=t-3$

$y=t^2+2t$

Solve the first equation for $t$ by adding 3 on both sides:

$x+3=t$ .

Plug into second equation:

$y=(x+3)^2+2(x+3)$

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:

$y=(x^2+6x+9)+(2x+6)$

$y=(x^2)+(6x+2x)+(9+6)$

$y=x^2+8x+15$

Not the desired result.

Choice 4:

$x=t^2$

$y=2t-3$

I'm going to solve the bottom equation for $t$ since I don't want to deal with square roots.

Add 3 on both sides:

$y+3=2t$

Divide both sides by 2:

$\frac{y+3}{2}=t$

Plug into equation 1:

$x=(\frac{y+3}{2})^2$

This is not the desired result because the $y$ variable will be squared now instead of the $x$ variable.

Choice 5:

$x=t+1$

$y=t^2+4t$

Solve the first equation for $t$ by subtracting 1 on both sides:

$x-1=t$ .

Plug into equation 2:

$y=(x-1)^2+4(x-1)$

Distribute and use the binomial square identity used earlier:

$y=(x^2-2x+1)+(4x-4)$

$y=(x^2)+(-2x+4x)+(1-4)$

$y=x^2+2x+-3$

$y=x^2+2x-3$ .

This is the desired result.

3 0

4 years ago

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Help pls with math lotsss of points!!!

sveticcg [70]

Answer:

5x^2+22x-12 x cannot be -5, -4, -2

(x+5)(x+4)(x+2)

Step-by-step explanation:

In order to solve this, your denominator must be the same. Let's start by writing out the two different quadratic formulas:

x^2 + 6x + 8 <-- This should factor out to (x+4)(x+2)

x^2 + 7x + 10 <-- This should factor out to (x+5)(x+2)

Now that you have factored out the two quadratics, plug them into the equation.

5x - 3

(x+4)(x+2) (x+5)(x+2)

Now as we know, -2 cannot be x because it will turn the entire equation undefined. Multiple top and bottom with (x+5) on the right side and (x+4) on the left side.

5x (x+5) - 3(x+4)

(x+5)(x+4)(x+2) (x+5)(x+4)(x+2)

Focus on the top. 5x(x+5) will turn out to be 5x^2+25x. 3(x+4) will turn out to be 3x+12. Combine the two equations because now they are equal to each other and do the subtraction:

5x^2+25x - (3x+12) = 5x^2+22x-12 x cannot be -5, -4, -2

(x+5)(x+4)(x+2) (x+5)(x+4)(x+2)

4 0

2 years ago