Here's a way to do it.
Let 4e +2 = 5n +1 . . . . . . for some integer n
Then e = (5n -1)/4 = n + (n -1)/4
We want (n-1)/4 to be an integer, so let it be integer m.
... m = (n -1)/4
... 4m = n -1
... 4m +1 = n
Substituting this into our expression for e gives
... e = (5(4m+1) -1)/4 = (20m +4)/4 = 5m +1
e = 5m+1 for any integer m
A. A 90° counterclockwise rotation of trapezoid JKLM about the origin will move angle L onto angle R.
Step-by-step explanation:
Since both the trapezoids, trapezoid JKLM and PQRS are congruent, we can do any transformation, may be rotation, reflection and translation.
A 90° counterclockwise rotation of trapezoid JKLM about the origin will move angle L onto angle R is the true statement others are incorrect statements.
When the Preimage is rotated 90° counterclockwise rotation, then its coordinates (x,y) changed into (-y,x)
6 positive tiles because there’s 6 negative so 6 positive will cancel it out
Graph of f(x-3) is compressed by a factor of 
horizontally of f(x).
<u>Step-by-step explanation:</u>
We have, the graph of f(x)= 
, on replacing f(x) by f(x-3) we get:
= 
.Below shown are the images for graph of f(x) and f(x-3). Both are functions are exponential , and so having exponential graph but f(x-3) is compressed by a factor of horizontally . Domain and range of both functions are same i.e. F(x) & f(x-3) domain & range are same , just difference in graph : 
.
Answer:
The product of 3 and a variable n plus 7
Step-by-step explanation:
