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Ad libitum [116K]
2 years ago
15

Question 9 Annabelle lives at Bermondsey in London. She has to speak at a conference in Birmingham at 10.30am. It will take her

an hour from her home to get to Euston Rail Station, from where she will get a train to Birmingham. The train journey from Euston to Birmingham is an hour and 10 minutes. Trains to Birmingham run at the following times: 5 minutes past the hour, 25 minutes past the hour and 45 minutes past the hour. The meeting venue in Birmingham is a 5-minute walk from the station. What is the latest time that Annabelle can leave home, if she is to make it on time for the meeting in Birmingham? Show your working. (8 marks)​
Mathematics
1 answer:
JulijaS [17]2 years ago
5 0

Answer:

Step-by-step explanation:

working backwards

the five minute walk

10:30 - 0:05 = 10:25

train ride to Birmingham

10:25 - 1:10 = 9:15

Next earliest train departure time

9:05

Getting to Euston Station

9:05 - 1:00 = 8:05 am

Probably wise to leave a couple of minutes earlier to allow for minor emergencies on the way to Euston Station or to account for potential clock synchronization errors.

The train schedule already allows an additional 10 minutes of buffer time after boarding.

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A. median and mode

B. Mean

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a. Mean = sum of all values / numbers of values = 1804 / 23 = 78.4. this eliminates the mean and leaves the median and mode, both of which are 62.  

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b. Only the Mean would be affected. It would move from 78.4 to 80.6. (calculated as 1853 / 23). The median and mode would not be affected as the 62 would remain the middlemost value and the most frequent.

 

c. Removing the largest value would result in the mean changing. The mean would now be 73 (calculated as 1607 / 22). Since the values are no longer 23, but now 22, the median would be the average of the 2 middlemost values, ((62+62) / 2) which would still result in 62 as the median.  

d. we use the Five number summary:  

Median / Interquartile Range = 62

First Quartile / Q1 = (51 +57) / 2 = 54

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Maximum = 197 ; therefore Range = (197 - 2) = 195.

Please see attached box and whisker plot. The distribution is positively skewed.

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