HELP!! PLEASE!! (Fill in blank)

Mathematics

2 answers:

Reika [66]2 years ago

8 0

I need more info ?!

Ilya [14]2 years ago

3 0

Answer:

help me

Step-by-step explanation:

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Select the objects that hold the same amount of liquid as a 128−fluid-ounce jug. Select all that apply. A three 8−ounce fluid gl

Salsk061 [2.6K]

The correct answers are C, D, and E.

1 quart = 32 fl oz
1 pt = 16 oz

Using these conversions you will multiply the number of quarts or pints by the number of ounces in each and then add the totals together to find if they equal 128 oz.

C. 4 x 32 = 128 oz
D. 2 x 32 + 8 x 8 = 128 oz
E. 3 x 32 + 2 x 16 = 128 oz

8 0

2 years ago

Rationalize the numerator or denominator, and simplify:

allochka39001 [22]

$\dfrac{\sqrt[3]{x+h}-\sqrt[3]x}h\times\dfrac{\sqrt[3]{(x+h)^2}+\sqrt[3]{x(x+h)}+\sqrt[3]{x^2}}{\sqrt[3]{(x+h)^2}+\sqrt[3]{x(x+h)}+\sqrt[3]{x^2}}=\dfrac{(\sqrt[3]{x+h})^3-(\sqrt[3]x)^3}\cdots$
$=\dfrac{x+h-x}\cdots=\dfrac h\cdots$

The $h$ s then cancel, leaving you with the $\cdots=\sqrt[3]{(x+h)^2}+\sqrt[3]{x(x+h)}+\sqrt[3]{x^2}$ term.

If it's not clear what I did above, consider the substitution $a=\sqrt[3]{x+h}$ and $b=\sqrt[3]x$ . Then

$a^3-b^3=(a-b)(a^2+ab+b^2)$
$\implies\dfrac{a-b}h=\dfrac{a-b}h\times\dfrac{a^2+ab+b^2}{a^2+ab+b^2}=\dfrac{a^3-b^3}{h(a^2+ab+b^2)}$

4 0

2 years ago

In a family with four children, what is the probabaility that 3 are girls and one is a boy

valkas [14]

If we write all the possible combinations for this problem, 4/16 or 1/4 would be the answer.

BGGG
GBGG
GGBG
GGGB

This is not taking into consideration the specific order of the children. In case the order will be necessary, the Girls need to be labeled differently and permutation formula needs to be used.

4 0

2 years ago

3. Using the sample size of 800 and the proportion 0.47, calculate the margin of error associated with the estimate of the propo

salantis [7]

Answer:

$ME=1.96\sqrt{\frac{0.47 (1-0.47)}{800}}=0.0346$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

We assume for this case a confidence level of 95%. In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by: