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xxTIMURxx [149]

3 years ago

10

The original price of a camera is $150. If a discount of 30% is given, what is the amount of this discount ?

1 answer:

shtirl [24]3 years ago

4 0

Question

The original price of a camera is $150. If a discount of 30% is given, what is the amount of this discount ?

150 : 100 * 30 =

45$ is your answer

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A rectangle has a perimeter of 26 units. The length of the rectangle is 2X+3 and the width is 3X. What is the width of the recta

densk [106]

Answer:

X = 2

Step-by-step explanation:

Divided 26 (total perimeter) by 4 = maximum side length possible = 26÷4 =.6.5

I used the trial and error technique

Guessed it was 2 working out to see if i was right or wrong:

Length: 2(2) + 3 = 4+3 = 7

Width: 3(2) = 6

7+7+6+6 = 26

Therefore X = 2

3 0

3 years ago

Mike and Ike are twins. Mike’s age is one more than twice a certain number. Ike’s age is 10 less than triple that same number. F

Misha Larkins [42]

Mike age is 3 less then twice the age of his brother nuke.
M = Mike's age now
N = Nuke's age now
M = 2N - 3

Ten years ago, four times nuke's age was one more mike's age.
M-10 = Mike's age 10 years ago
N-10 = Muke's age 10 years ago
4(N - 10) = 1 + M -10

what are their present ages

find M and N

substitute M = 2N - 3 into 4(N - 10) = 1 + M -10:

4(N - 10) = 1 + [2N - 3] - 10
4N - 40 = 2N - 12
2N = 28
N = 14

M = 2(14) - 3 = 28 - 3 = 25

Mike is 25 and Nuke is 14.

check:
4(14 - 10) = 4(4) = 16 = 26 -10 = 1 + 25 - 10

4 0

2 years ago

Lucy wants to be exempt from her semester exam. In order for that to happen, she has to average an 85 over 3 test grades. Her fi

anastassius [24]

Answer:

<em>Grades to be scored in 3rd exam = 88</em>

Step-by-step explanation:

Given that average of 3 numbers is 85.

First two numbers are 81 and 86.

To find:

3rd number so that average is 85

Solution:

Let the third number = $x$

Formula for average is:

$Average = \dfrac{Sum\ of\ numbers}{Total\ count\ of\ numbers}$

Here, sum of numbers = $81+86+x =167+x$

Total count of numbers = 3

$85 = \dfrac{167+x}{3}\\\Rightarrow x=255-167\\\Rightarrow \bold{x=88}$

<em>Grades to be scored in 3rd exam = 88</em>

8 0

2 years ago

Find the median, first quartile, third quartile, interquartile range, and any outliers for each set of data. 111, 68, 93, 88, 74

lilavasa [31]

Answer:

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

Step-by-step explanation:

Given the data:

111, 68, 93, 88, 74, 152, 119, 87, 88, 105, 84, 102, 151, 115, 112

Ordered data : 68, 74, 84, 87, 88, 88, 93, 102, 105, 111, 112, 115, 119, 151, 152

Sample size, n = 15

The first quartile, Q1 = 1/4(n+1)th term

Q1 = 1/4(15+1)th term

Q1 = 1/4(16) = 4th term

Q1 = 87

The Median , Q2 = 1/2(n+1)th term

Q2 = 1/2(15+1)th term

Q2 = 1/2(16) = 8th term

Q2 = 102

The third quartile, Q3 = 3/4(n+1)th term

Q3 = 1/4(15+1)th term

Q3 = 3/4(16) = 12th term

Q3 = 115

The interquartile range, IQR = Q3 - Q1

IQR = (115 - 87) = 28

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

4 0

2 years ago

One thousand raffle tickets are sold at $2 each. Six prizes will be awarded, one first prize worth $500, two second prizes worth

zvonat [6]

Oliver would have a 1/1000 chance of getting $500, a 2/1000 chance of earning $300, and a 3/1000 in earning $1000. He would have a 994/1000 chance of making no money back

8 0

3 years ago