It could be written as 8w the simplified version of the example.
Or you could write it as 2(3w + w) which is 2 time the length and width.
Answer:
Step-by-step explanation:
At the start of the day there are g pounds of gravel in the quarry.
Then it says that there were 300 pounds added to the mound, so at this point the pounds of gravel in the mound are now g+300.
Then two orders of 700 pounds are sold and removed from the mound. That means they removed 700 pounds from the mound 2 times. Therefore at this point the pounds of gravel in the mound are now g+300-700-700.
Then it says that at this point, the amount of pounds in the mound are 1500. Hence we get
To solve for g we just add 700 two times to both sides of the equation, and subtract 300 from both sides of the equation, getting:
And so 
1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :
i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.
ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:
a^{2}=b ^{2}+c ^{2}-2bc(cosA)
2.
20^{2}=9 ^{2}+13 ^{2}-2*9*13(cosA) 400=81+169-234(cosA) 150=-234(cosA) cosA=150/-234= -0.641
3. m(A) = Arccos(-0.641)≈130°,
4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc
22 need more
150-56=94
20*3 = 60
94-60 = 34
34-12= 22
