It takes Joey 1/16 of an hour to write one thank you card. How many cards can he write in 3/4 of an hour?

Alex is making puppets for a show. He bought all the string needed for $125. It costs $18 for the remaining materials to make ea

Alexus [3.1K]

Alex bought all the string needed for $125.

It costs $18 for the remaining materials to make each puppet.

So if we closely observe then we see that here $125 is the fixed cost because its not going to change with number of puppets.

And the variable cost is $18.

In this case we can model a Total cost function C(x) for for x number of puppets as below

$C(x)=125+18x\\ \\ \text{Here x is the number of puppets}\\ \\ \text{Since in our case the number of puppets is 50 so replace x by 50 we get }\\ \\ C(50)=125+18*50\\ \\ C(50)=125+900\\ \\ C(50)=1025 \ dollar.$

The total cost to make 50 puppets=$1025

3 0

2 years ago

Read 2 more answers

PLEASE HELP!! URGENT!! i will mark brainliest if its right!! In the figure below, ∠DEC ≅ ∠DCE, ∠B ≅ ∠F, and DF ≅ BD. Point C is

zvonat [6]

Answer:

See below.

Step-by-step explanation:

This is how you prove it.

<B and <F are given as congruent.

This is 1 pair of congruent angles for triangles ABC and GFE.

<DEC and <DCE are given as congruent.

Using vertical angles and substitution of transitivity of congruence of angles, show that angles ACB and GEF are congruent.

This is 1 pair of congruent angles for triangles ABC and GFE.

Now you need another side to do either AAS or ASA.

Look at triangle DCE. Using the fact that angles DEC and DCE are congruent, opposite sides are congruent, so segments DC and DE are congruent. You are told segments DF and BD are congruent. Using segment addition postulate and substitution, show that segments CB and EF are congruent.

Now you have 1 pair of included sides congruent ABC and GFE.

Now using ASA, you prove triangles ABC and GFE congruent.

7 0

3 years ago

Val needs to find the area enclosed by the figure. The figure is made by attaching semicircles to each side of a 58-by-58 squar

Savatey [412]

Answer:

We need to find the area of the semicircles + the area of the square.

The area of a square is equal to the square of the lenght of one side.

As = L^2 = 58m^2 = 3,364 m^2

Now, each of the semicircles has a diameter of 58m, and we have that the area of a circle is equal to:

Ac = pi*(d/2)^2 = 3.14*(58m/2)^2 = 3.14(27m)^2 = 2,289.06m^2

And the area of a semicircle is half of that, so the area of each semicircle is:

a = (2,289.06m^2)/2 = 1,144.53m^2

And we have 4 of those, so the total area of the semicircles is:

4*a = 4* 1,144.53m^2 = 4578.12m^2

Now, we need to add the area of the square 3,364 m^2 + 4578.12m^2 = 7942.12m^2

This is nothing like the provided anwer of Val, so the numbers of val may be wrong.

4 0

3 years ago

What is $6.25 marked up 25%

Marta_Voda [28]

Answer:

$6.25 marked up 25% is $7.81

Step-by-step explanation:

First, you have to find what 25% is of 6.25.

Step 1: Our output value is 25.

Step 2: We represent the unknown value with x.

Step 3: From step 1 above, 25=100%.

Step 4: Similarly, x=6.25%.

Step 5: This results in a pair of simple equations:

25=100%(1)

x=6.25%(2)

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

x 6.25

Step 7: Again, the reciprocal of both sides gives

25 100

x= 1.5625

x≈ 1.56

Once you've known what 25% is, you add it to 6.25.

1.56+6.25= 7.81

7 0

3 years ago

Calculate the surface area and volume of the shape below.

pav-90 [236]

Surface area

Let's calculate the surface area of the rectangular block. It has length, width and height of L = 15, W = 5, H = 8. The surface area is going to be

SA = 2*(LW+WH+LH)

SA = 2*(15*5+5*8+15*8)

SA = 470

This is without the cylinder attached to the top surface. If we account for that, then we'll have to subtract off the area of the circle covered up which is

pi*r^2 = pi*3^2 = 9pi = 28.27433 approximately

So 470-28.27433 = 441.72567 is the approximate surface area of the rectangular block after we subtract off the circular portion covered up by the cylinder.

----------

The lateral surface area of the cylinder is approximately

2*pi*r*h = 2*pi*3*4 = 24pi = 75.39822

Which adds onto the top circular area of 28.27433 to get 28.27433+75.39822 = 103.67255

Meaning that 103.67255 is the surface area for the cylinder portion. Again we don't worry about the bottom portion as it's not part of the outer surface.

---------

Overall, the total surface area of this compound 3D figure is

(surface area for rectangular portion) + (surface area cylinder portion) = 441.72567+103.67255 = 545.39822

When rounding to the nearest whole number, the total surface area is about 545 square cm

<h3>Answer: 545 square cm</h3>

============================================================

Volume

The rectangular block has volume L*W*H = 15*5*8 = 600 cubic cm

The cylinder has volume pi*r^2*h = pi*3^2*4 = 113.0973355 approximately

Add the two volumes to get 600+113.0973355 = 713.0973355 and this rounds to 713. We don't have to do any subtraction in this section.

<h3>Answer: 713 cubic cm</h3>

4 0

3 years ago