So he is over budget by $90 and he needs to allocate his bills to allow for it
Answer:
The size of the cardboard should be 
Step-by-step explanation:
The diagram for this question is shown on the first uploaded image
The volume of the box is 
The length and the Width of the card is
L = W = Z
From the question we are told that 7 in squares were cut from each corner
So the length and the width of the box would be
L = W = (Z - 7)
And the height would be H = 7 in
Mathematically the volume of the box can be represented as

So the Volume would be
Substituting values


=> 

Answer:
9
Step-by-step explanation:
Answer:
A.
In 4231, the value of the digit 3 is 110 less than the value of the digit 3 in 3421.
Step-by-step explanation:
We can see that the value of 3 In 4231 is in ten while the value of 3 in 3421 is in thousands.
So to get the actual division factor, let's take 3300 and divide it by 30,
3300/30 = 110
So it's clear already, that the value of 3 in 4231 is 110 times less to the value in 3421
Step-by-step explanation:Let number of 49 cents =A
Let number of 33 cents=B
<u>A+B=45 equation 1</u>
1 $=100 cents
49 cents =.49 dollar
33 cents=.33 dollar
so .<u>49A+.33B=17.89 equation 2</u>
Add equation 1 and equation 2
since these are simultaneous equations
.49A+.33B=17.89
A+ B=45
so divide equation 2 by 100 we get
49A+33B=1789
A+B =45 multiply equation 1 by 33 on both the sides we get
<u>33A+33B=1485 equation 3</u>
so subtract equation 3 from equation 2 we get
49A+33B=1789 equation 2
<u>33A+33B=1485 equation 3</u>
<u>16A+0 =304</u>
16A=304
A=304/16
A=19
putting nalue of A in equation 1 we get
A+B=45
19+B=45
B=45-19
B=26
so number of 49 cent stamps are 19
and number of 33 cent stamps are 26