At first glance, it seems like a good estimate; big numbers make bigger number.
But, this is multiplication, which means big numbers will make an extraordinarily big number, in proportion to the numbers themselves.
If you round 31 3/4 up to 32, you can multiply that by 50. To make the estimate easier, multiply 50 by 2,
50 x 2 = 100
Take the zeros off 50 and 30 to make this a bit simpler, and multiply 5 by 3,
5 x 3 = 15
Add each of the zeros you took off to the 15 to make 1500 (1 zero was taken off 50, and 1 off of 30),
And then add 1500 to that other 100
1500 + 100 = 1600
A good estimate for 50 x 31 3/4 would be 1600, not 800.
Therefore,
No. Brenda's estimate of 800 is NOT a good estimate.
80 cups
1 qal X 4 qts x2pts x2 cups= 16 cups in one gallon
16x5=80
Answer:
The player's height is 3.02 standard deviations above the mean.
Step-by-step explanation:
Consider a random variable <em>X</em> following a Normal distribution with parameter <em>μ</em> and <em>σ</em>.
The procedure of standardization transforms individual scores to standard scores for which we know the percentiles (if the data are normally distributed).
Standardization does this by transforming individual scores from different normal distributions to a common normal distribution with a known mean, standard deviation, and percentiles.
A standardized score is the number of standard deviations an observation or data point is above or below the mean.
The standard score of the random variable <em>X</em> is:

These standard scores are also known as <em>z</em>-scores and they follow a Standard normal distribution, i.e. <em>N</em> (0, 1).
It is provided that the height of a successful basketball player is 196 cm.
The standard value of this height is, <em>z</em> = 3.02.
The <em>z</em>-score of 3.02 implies that the player's height is 3.02 standard deviations above the mean.