log (m + n) = log m+ log n and proved it m =n/n-1
Given;
If log (m + n) = log m+ log n
To show that the m =n/n-1
Now, According to the question:
We know that,
Log (m + n) = log m + log n
Log (m + n ) = log (mn). [log a + log b = log ab ]
Cancelling the log on both sides.
then,
m + n = mn
=> n = mn - m
=> n = m (n - 1)
=> m = n / n - 1
Hence Proved
log (m + n) = log m+ log n and proved it m =n/n-1
What is Logarithm?
A logarithm is the power to which a number must be raised in order to get some other number (see Section 3 of this Math Review for more about exponents). For example, the base ten logarithm of 100 is 2, because ten raised to the power of two is 100: log 100 = 2.
Learn more about Logarithm at:
brainly.com/question/16845433
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Answer:
21, 6, 12
Step-by-step explanation:
your welcome:)
Answer:
292.5
Step-by-step explanation:
Roberta earns $262.50 per week so i added 262.50 and 30 and got 292.5
Answer:
2(x-√a)² + x - √a +1
Step-by-step explanation:
use x-√a as value for x
f(x-√a) = 2(x-√a)² + x - √a +1
It looks like you have number 1 correct.
For number 2, what is alike is the exponent of 2. To combine them, add them together. You can do this because they are like terms (aka have the same variable and exponent)
3-4-1= -2. The answer is -2x^2
For number 3, those are not like terms. They either do not have the same variable (x or y) or they do not have the same exponent (1 or 2)
Both the exponent and the variable have to be the same for it to be a like term.
