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Schach [20]
3 years ago
12

Luke has two summer jobs. During the week he works in the grocery store, and on the

Mathematics
1 answer:
TiliK225 [7]3 years ago
8 0

Hello! First, let's get some important information:

Luke works in the:

  • week → grocery store → $16/hour
  • weekend → nursery → $22/hour

Now, let's analyze the questions:

<h3>a) How much does he earn if he works 5 hours at the grocery store and 8 hours at the nursery? </h3>

To find the amount he will receive, you must multiply the amount of 1 hour by the number of hours worked. Look:

\mathrm{Grocery\:Store}\\\\\$16 \cdot 5 \:\mathrm{hours}= \$80\\\$22 \cdot 8\:\mathrm{hours}=\$176

<h3>b) How much does he earn if he works g hours at the grocery store and n hours at the nursery?</h3>

\$16 \cdot \mathrm{g} \:\mathrm{hours}= \$16\cdot\mathrm{g}\\\$22 \cdot \mathrm{n}\:\mathrm{hours}=\$22\cdot\mathrm{n}

<h3>c) Total pay, 5 hours at the grocery store and 8 hours at the nursery:</h3>

You'll just have to just add the value in each of the jobs:

$80 + $176 = $256

<h3>d) Total pay, g hours at the grocery store and n hours at the nursery:</h3>

Adding the values of each job:

$16g + $22n

Hope this helps!

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6 0
3 years ago
the marks in an examination for a Physics paper have normal distribution with mean μ and variance σ2 . 10% of the students obtai
Blababa [14]

Let X be the random variable for the number of marks a given student receives on the exam.

10% of students obtain more than 75 marks, so

P(X>75)=P\left(\dfrac{X-\mu}\sigma>\dfrac{75-\mu}\sigma\right)=P(Z>z_1)=0.10

where Z follows a standard normal distribution. The critical value for an upper-tail probability of 10% is

P(Z>z_1)=1-F_Z(z_1)=0.10\implies z_1=F_Z^{-1}(0.90)

where F_Z(z)=P(Z\le z) denotes the CDF of Z, and F_Z^{-1} denotes the inverse CDF. We have

z_1=F_Z^{-1}(0.90)\approx1.2816

Similarly, because 20% of students obtain less than 40 marks, we have

P(X

so that

P(Z

Then \mu,\sigma are such that

\dfrac{75-\mu}\sigma\approx1.2816\implies75\approx\mu+1.2816\sigma

\dfrac{40-\mu}\sigma\approx-0.8416\implies40\approx\mu-0.8416\sigma

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4 years ago
If f(x) is an exponential function where f(-1.5) 26 and
mariarad [96]

Answer:

f(10) = 1147.25

Step-by-step explanation:

Given

f(-1.5) = 26

f(5.5) = 7

Required

f(10)

An exponential function is represented as:

f(x) = ab^x

f(-1.5) = 26 impleies that:

26 = ab^{-1.5} --- (1)

f(5.5) = 7 implies that

7 = ab^{5.5} --- (2)

Divide (2) by (1)

26/7 = ab^{-1.5}/ab^{5.5}

3.71429 = b^{-1.5+5.5}

3.71429 = b^{4}

Take 4th root

b = 1.39

Substitute b = 1.39 in 26 = ab^{-1.5}

26 = a * 1.39^{-1.5}

26 = a * 0.6102

Solve for (a)

a = 26/0.6102

a = 42.61

f(10) is calculated as:

f(10) = ab^{10}

f(10) = 42.61 * 1.39^{10}

f(10) = 1147.25

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3 years ago
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Vedmedyk [2.9K]
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3 years ago
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fenix001 [56]

Answer:

18

Step-by-step explanation:

Product of 7 and a number is 126.

Let's form the equation,

→ 7 × x = 126

The required value of x will be,

→ 7 × x = 126

→ x = 126/7

→ [ x = 18 ]

Hence, the number is 18.

6 0
2 years ago
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