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kow [346]
3 years ago
7

Show that 6 is a quaint number.

Mathematics
1 answer:
Alika [10]3 years ago
6 0

Answer:

6=2+2+2

Step-by-step explanation:

-In mathematics, a quaint number is a number that can be written as the sum of two or more  prime numbers.

-The multiple divisors of 6 in a factor tree are 2,2 and 2

-6 can thus be written as 2+2+2:

6=2+2+2

-Hence 6 is a quaint number

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In general: look for what the terms have in common. for example, take the binomial 2x² - 4x. you would be able to factor out a "2" because of the coefficients, and both terms have an "x" -- you can take that out too. that makes your GCF 2x. technically, what you're doing with factoring is dividing the terms by your GCF--2x² divided by 2x leaves you with x, and 4x divided by 2x leaves you with two. that's how you end up with (x - 2) in your binomial. your result looks like this: 2x(x - 2).

if you have any specific binomials you need help with, feel free to send me a message or comment on this and i'll see if i can help. if you're just asking in general, then just remember to look for what the terms have in common, then take it out. 
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3 years ago
a CANDLE IS IN THE SHAPE OF A TRIANGULAR PRISM.tHE BASE Has an area of30 squareinches. The candle hs a height of 6 inches. Find
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The volume of a triangular prism by definition is given by:
 V = (Area of the base) * (height)
 Substituting the values we have:
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 Answer:
 
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V = 180 in ^ 3
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Which number sentence is in the same family facts.
DanielleElmas [232]
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What is 1/7^9 × 1/7^-6
artcher [175]
\bf \cfrac{1}{7^9}\cdot \cfrac{1}{7^{-6}}\implies \cfrac{1\cdot 1}{7^9\cdot 7^{-6}}\implies \cfrac{1}{7^{9-6}}\implies \cfrac{1}{7^3}\implies \cfrac{1}{343}
5 0
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Gavin is starting a running plan to train for a race. In the first week of his running plan, Gavin will run 5 miles. The plan ca
iren2701 [21]
<h2>Answer:</h2><h2>Gavin would be expected to run during 36.5 miles during his 11th week of the training plan</h2>

Step-by-step explanation:

In the first week of his running plan,the number of miles covered = 5 miles

Weekly mileage will increase by 3.5 miles every week.

At the end of second week, the number of miles covered = 5 + 3.5 = 8.5

At the end of third week, the number of miles covered = 8.5 + 3.5 = 12

The series is 5, 8.5, 12, ...

Consider this as an AP, where a = 5, d = 3.5

By formula,  

 a_{n}  = a + (n-1)d

Substituting the values in the above equation, we get

 a_{11} = 5 + (10-1) 3.5

= 5 +(9)3.5

= 5 + 31.5

=36.5 miles.

Gavin would be expected to run during 36.5 miles during his 11th week of the training plan

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