Ask question

Ask question

All categories

3 years ago

6

Like the alto in a choir the octavina plays the lower melody . what musical element does this tell?

1 answer:

Katena32 [7]3 years ago

7 0

<em>L</em><em>ike the alto in a choir the octavina plays the lower melody . what musical element does this tell?</em>

answer : melody....

You might be interested in

What is the oxidation number of the noble gases such as xenon and argon?

OLga [1]

Oxidation number for Xenon is XeOF2 and Argon is 0.

6 0

3 years ago

A disk with a rotational inertia of 5.0 kg. m2 and a radius of 0.25 m rotates on a frictionless fixed axis perpendicu-

diamong [38]

Answer:1.6 rad/s

Explanation:

Given

moment of Inertia of disk $I=5 kg-m^2$

radius of disc $r=0.25 m$

Force $F=8 N$

Torque $T=I\alpha =F\cdot r$

$5\times \alpha =8\times 0.25$

$\alpha =0.4 rad/s^2$

using

$\theta =\omega _0\times t+\frac{\alpha t^2}{2}$

$\pi =0+\frac{0.4t^2}{2}$

$2\pi =0.4t^2$

$t^2=5\pi$

$t=\sqrt{5\pi }$

$t=3.96 s$

$\omega =\omega _0+\alpha t$

$\omega =0+0.4\times 3.96$

$\omega =1.58 rad/s\approx 1.6 rad/s$

3 0

4 years ago

A physical property of gold is its

Irina18 [472]

Gold<span> is both malleable and ductile.</span>

8 0

3 years ago

Đoạn dây dẫn thẳng có dòng điện I chạy qua, đặt trong từ trường

umka21 [38]

<em>A straight piece of wire with a current I flowing through it is placed in a magnetic field</em>

<em>A straight piece of wire with a current I flowing through it is placed in a magnetic fielduniform and perpendicular to the magnetic field lines. Magnetic force acting on the string</em>

<em>A straight piece of wire with a current I flowing through it is placed in a magnetic fielduniform and perpendicular to the magnetic field lines. Magnetic force acting on the stringthere is a way</em>

4 0

3 years ago

Three resistors, 6.0-W, 9.0-W, 15-W, are connected in parallel in a circuit. What is the equivalent resistance of this combinati

ycow [4]

Answer:

2.9Ω

Explanation:

Resistors are said to be in parallel when they are arranged side by side such that their corresponding ends are joined together at two common junctions. The combined resistance in such arrangement of resistors is given by;

1/Req= 1/R1 + 1/R2 + 1/R3 .........+ 1/Rn

Where;

Req refers to the equivalent resistance and R1, R2, R3 .......Rn refers to resistance of individual resistors connected in parallel.

Note that;

R1= 6.0Ω

R2 = 9.0Ω

R3= 15.0 Ω

Therefore;

1/Req = 1/6 + 1/9 + 1/15

1/Req= 0.167 + 0.11 + 0.067

1/Req= 0.344

Req= (0.344)^-1

Req= 2.9Ω

3 0

3 years ago