The absolute pressure is given by the equation,

Here,  is absolute pressure,
 is absolute pressure, is atmospheric pressure and
 is atmospheric pressure and  is vacuum pressure.
 is vacuum pressure.
Therefore,

The gage pressure is given by the equation,
 .
.
Thus,
 .
.
In kn/m^2,
The absolute pressure,

The gage pressure,
 .
.
In lbf/in2
The absolute pressure,

The gage pressure,

In psi,
The absolute pressure,
 .
.
The gage pressure,

In  mm Hg
The absolute pressure,

The gage pressure,

 
        
             
        
        
        
If an atom gains electrons, it develops a negative charge equal to the number of electrons gained.
So the net charge on the copper atom which gained 2 electrons will be -2.
        
             
        
        
        
Answer:
F = 11 N
Explanation:
Given,
Mass of a block, m = 5 kg
Acceleration of the block, a = 2.2 m/s²
We need to find the force on the person's hand. Let it is F. We know that force is given by the product of mass and acceleration as follows :
F = ma
F = 5 kg × 2.2 m/s²
F = 11 N
So, the force on a person's hand is 11 N.
 
        
             
        
        
        
Answer:
This means that the kinetic energy of second object is 48times that of the first object 
Explanation:
Kinetic energy is the energy possessed by a body by virtue of its motion e.g motion of an accelerating car. Mathematically, 
Kinetic energy = 1/2mv² where;
m is the mass of the object 
v is the velocity of the object
If Object 1 of mass m moves with speed v in the positive direction, its kinetic energy will be expressed as;
K1 = 1/2mv²
For Object 2 of mass 3m moving with speed 4v in the negative x-direction, its kinetic energy can be expressed as;
K2 = 1/2(3m)(4v)²
K2 = 1/2(3m)(16v²)
K2 = (3m)(8v²)
K2 = 24mv²
To compare the kinetic energy of both bodies, we will take the ratio of K2:K1 to have;
K2/K1 = 24mv²/(1/2)mv²
K2/K1 = 24/(1/2)
K2/K1 = 48
K2 = 48K1
This means that the kinetic energy of second object is 48times that of the first object and moving in the negative x direction since the body of mass 3m initially moves in the negative x direction.
 
        
             
        
        
        
<h2>
Its velocity when it crosses the finish line is 117.65 m/s</h2>
Explanation:
We have equation of motion s = ut + 0.5 at²
         Initial velocity, u = 0 m/s
         Acceleration, a = ?
         Time, t = 6.8 s    
         Displacement, s = 1/4 mi =    400 meters
      Substituting
                       s = ut + 0.5 at²
                       400 = 0 x 6.8 + 0.5 x a x 6.8²
                       a = 17.30 m/s²
Now we have equation of motion v = u + at
      Initial velocity, u = 0 m/s
      Final velocity, v = ?
      Time, t = 6.8 s
       Acceleration, a = 17.30 m/s²
      Substituting
                       v = u + at  
                       v = 0 + 17.30 x 6.8
                       v = 117.65 m/s
Its velocity when it crosses the finish line is 117.65 m/s