if an object is falling on earth at a terminal velocity of 140 km/hr, does that mean that the acceleration is ZERO?
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Hi there!
We know that:
U = Potential Energy (J)
K = Kinetic Energy (J)
E = Total Energy (J)
At 10m, the total amount of energy is equivalent to:
U + K = 50 + 50 = 100 J
To find the highest point the object can travel, K = 0 J and U is at a maximum of 100 J, so:
100J = mgh
We know at 10m U = 50J, so we can solve for mass. Let g = 10 m/s².
50J = 10(10)m
m = 1/2 kg
Now, solve for height given that E = 100 J:
100J = 1/2(10)h
100J = 5h
<u>h = 20 meters</u>
Explanation:
(a) For an isothermal process, work done is represented as follows.
W =
Putting the given values into the above formula as follows.
W =
=
=
=
= 29596.78 J
or, = 29.596 kJ (as 1 kJ = 1000 J)
Therefore, the required work is 29.596 kJ.
(b) For an adiabatic process, work done is as follows.
W =
=
=
= 49.41 kJ
Therefore, work required to produce the same compression in an adiabatic process is 49.41 kJ.
(c) We know that for an isothermal process,
or,
=
= 11 atm
Hence, the required pressure is 11 atm.
(d) For adiabatic process,
or,
=
= 28.7 atm
Therefore, required pressure is 28.7 atm.