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3 years ago

I need help thanks in advance

Mathematics

1 answer:

sergij07 [2.7K]3 years ago

6 0

Answer:

Step-by-step explanation:

The rule is if 2 chords intersect inside a circle, then the measure of the angle formed is one half the um of the measure of the arcs intercepted by the angle and its vertical angle. In other words, angle TSU = 1/2(arc TU + arc MV):

angle TSU = 1/2(90 + 80) and

angle TSU = 1/2(170) and

angle TSU = 85

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crimeas [40]

Answer:

The zeros are:

$x =4, x=2, x = 5$

The function has three distinct real zeros.

Hence, option (B) is true.

Step-by-step explanation:

Given the expression

$h\left(x\right)=\left(x-4\right)^2\left(x^2-7x+\:10\right)$

Let us determine the zeros of the function by putting h(x) = 0 and solving the expression

$0=\left(x-4\right)^2\left(x^2-7x+10\right)$

switch sides

$\left(x-4\right)^2\left(x^2-7x+10\right)=0$

$x^2-7x+\:10=\left(x-2\right)\left(x-5\right)$

$\left(x-4\right)^2\left(x-2\right)\left(x-5\right)=0$

Using the zero factor principle

$\mathrm{If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$x-4=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0$

$x =4, x=2, x = 5$

Thus, the zeros are:

$x =4, x=2, x = 5$

It is clear that there are three zeros and all the zeros are distinct real numbers.

Therefore,

The function has three distinct real zeros.

Hence, option (B) is true.

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pickupchik [31]

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