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vagabundo [1.1K]
3 years ago
5

What is the greatest common factor of 16 and 48?

Mathematics
2 answers:
andrew-mc [135]3 years ago
8 0

Answer:

16

Step-by-step explanation:

Alborosie3 years ago
3 0

Answer:

16

Step-by-step explanation:

The factors of 16 are: 1, 2, 4, 8, 16

The factors of 48 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48

Then the greatest common factor is 16.

Hope this helped

:)

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(-2-√3) (-2+√3) when simplified is​
Ksivusya [100]

Answer:

=1

Step-by-step explanation:

(-2-√3)(-2+√3)

=-2(-2+√3)-√3(-2+√3)

=4-2√3+2√3-√9

=4-3

=1

5 0
3 years ago
Hiiii please help ASAP I really need this :)))) please I’m praying somebody helps and gives a correct answer
Sauron [17]

Answer:

1.25

Step-by-step explanation:

100 divided by 4 = 25

60 divided by 4 = 15

30 divided by 4 = 7.5

5 divided by 4 = 1.25

3 0
3 years ago
Am i correct i chose c but i might think is wrong (valid answer only!!)
hoa [83]

Answer:

You are absolutely correct!

Step-by-step explanation:

The correct answer is C!

Hope this helps you realize!

8 0
2 years ago
Step by step workout of ;<br> log x^3+log 5x=5 log 2-log 2/5
Charra [1.4K]

Answer:

x = 2

Step-by-step explanation:

log  \: {x}^{3}  + log \: 5x = 5log \: 2 - log \:  \frac{2}{5}  \\  \\  \therefore \: log( {x}^{3}  \times 5x) = log  {2}^{5} - log \:  \frac{2}{5}  \\  \\ \therefore \: log( 5{x}^{4}) = log 32 - log \:  \frac{2}{5} \\  \\ \therefore \: log( 5{x}^{4}) = log  \bigg(32  \times  \frac{5}{2}  \bigg) \\  \\ \therefore \: log( 5{x}^{4}) = log  \bigg(16  \times  5) \\  \\ \therefore \: 5{x}^{4}=  16  \times  5 \\  \\ \therefore \: {x}^{4}=   {2}^{4}   \\  \\  \huge \purple{ \boxed{\therefore \: {x} = 2}}

4 0
3 years ago
Consider the following planes. x + y + z = 6, x + 7y + 7z = 6 (a) Find parametric equations for the line of intersection of the
Lelechka [254]

Answer:

a.x=6,y=-6t,z=6t

b.\theta=29.5^{\circ}

Step-by-step explanation:

We are given that

x+y+z=6

x+7y+7z=6

a.Substitute z=0

x+y=6...(1)

x+7y=6..(2)

Subtract equation (1) from equation (2)

6y=0

y=0

Substitute y=0 in equation(1)

x=6

The point (6,0,0) lie on a line.

r_0=(x_0,y_0,z_0)=(6,0,0)

Let A=

B=

A\times B=\begin{vmatrix}i&j&k\\1&1&1\\1&7&7\end{vmatrix}

A\times B=i(7-7)-j(7-1)+k(7-1)=-6j+6k

Therefore, the vector a'=(a,b,c)=

Line is parallel to vector a' and passing through the point (6,0,0).

The parametric equation is given by

x=x_0+at,y=y_0+bt,z=z_0+ct

Using the formula

The parametric equation is given by

x=6,y=-6t,z=6t

Angle between two plane

a_1x+b_1y+c_1z=d_1

and a_2x+b_2y+c_2z=d_2

cos\theta=\frac{(a_1,b_1,c_1)\cdot (a_2,b_2,c_2)}{\sqrt{a^2_1+b^2_1+c^2_1}\cdot \sqrt{a^2_2+b^2_2+c^2_2}}

Using the formula

cos\theta=\frac{(1,1,1)\cdot(1,7,7)}{\sqrt{1+1+1}\times \sqrt{1+7^2+7^2}}

cos\theta=\frac{1+7+7}{\sqrt 3\times 3\sqrt{11}}

cos\theta=\frac{15}{3\sqrt{33}}}=\frac{5}{\sqrt{33}}

\theta=cos^{-1}(0.87)=29.5^{\circ}

Where \theta in degree.

3 0
3 years ago
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