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2 years ago

3f-23=2f+6can u do it quick i have an exam

Mathematics

1 answer:

Pachacha [2.7K]2 years ago

8 0

Answer:

3f - 2f = 6 + 23( collection of like terms)

f = 29

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PLEASE HELP!!!!!!

slava [35]

9514 1404 393

Answer:

A: (3x +4)

B: (4x +5y) × (4x -5y)

Step-by-step explanation:

<u>Part A</u>:

Since we know the trinomial is a perfect square, we know the terms of each binomial factor are the square roots of the first and last terms of the trinomial.

9x² +24x +16 = (√(9x²) +√16)² = (3x +4)²

The side of the square is 3x+4.

<u>Part B</u>:

The difference of squares is factored like this:

a²-b² = (a +b)(a -b)

The given area expression is the difference of squares with ...

a = 4x, b = 5y

so, the factorization is ...

16x² -25y² = (4x +5y)(4x -5y)

The dimensions of the rectangle are (4x+5y) by (4x-5y).

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3 years ago

Can someone help me please?

Shtirlitz [24]

The image isn’t loading for me , try reuploading

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3 years ago

What's the difference between 4.5 and -3.5

suter [353]

Answer:

4.5 and -3.5 are different numbers for one then on is positive and one is negative

Step-by-step explanation:

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3 years ago

Someone please help me with this math question

Molodets [167]

Answer:

3rd one

Step-by-step explanation:

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3 years ago

2. In the circle shown, secants PE and PF have been drawn such that mCE  82 , mDF  98 and the ratio 3. In circle O, tangent

Andrew [12]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The arc PR is $\theta _{PR} = 84$

Step-by-step explanation:

A descriptive diagram of the diagram given in the question is shown on the first uploaded image

In the circle tangent $\= {M \= Q}$ , secant $PE$ and chord $PF$ are drawn

given that $\theta _ {MPQ} = 102^o$ , $\theta _{M} = 60^o$

The objective is to determine PR

From the diagram we see that MQ is a straight which implies that the the angle

$\theta_{NPM} = 180 -102$

$\theta_{NPM} = 78^o$

Now looking at triangle NMP we see that

$\theta _{MNP} = 180 -[ \theta_{NMP} + \theta _{NPM}]$

$\theta _{MNP} = 180 - [60 + 78 ]$

$\theta _{MNP} = 42 ^o$

Now the measure of an inscribed angle is half the measure of its arc intercepted, this statement is the inscribed angle theorem

So with the knowledge

Then

$\theta_{RNP} = \frac{1}{2} \theta_{PR}$

Looking at the diagram we see that

$\theta _{MNP} = \theta_{RNP} = 42 ^o$

$42 = \frac{1}{2} \theta _{PR}$

$\theta _{PR} = 2 * 42$

$\theta _{PR} = 84$

7 0

3 years ago

3f-23=2f+6can u do it quick i have an exam​

3f-23=2f+6can u do it quick i have an exam