Question

A right circular cylinder has a height of 20 1/2 ft and a diameter 1 1/5 times its height.

Answer 1

Answer:

$\sf 9738 \frac{5373}{10.000} \: ft \approx 9738,5373 \: ft$

Step-by-step explanation:

Cylinder radius length

diameter = (20½ × 1 ⅕)

diameter = $\sf \frac{41}{2} \times \frac{6}{5}$

diameter = $\sf \frac{41 \times 6}{2 \times 5}$

diameter = $\sf \frac{246}{10} \: ft$

r = $\sf \frac{246}{10} \times \frac{1}{2}$

r = $\sf \frac{246}{20}$

r = $\sf \frac{123}{10} \: ft$

Cylinder Volume

Volume = π × r² × t

Volume = 3.14 × $\sf (\frac{123}{10})²$ × 20½

Volume = 3.14 × $\sf \frac{15.129}{100}$ × 20½

Volume = $\sf \frac{2.375.253}{5000}$ × 20½

Volume = $\sf 9738 \frac{5373}{10.000} \: ft \approx 9738,5373 \: ft$

Conclusion:

Cylinder Volume is $\sf 9738 \frac{5373}{10.000} \: ft \approx 9738,5373 \: ft$.

Answer 2

• Height=h=20-1/2=20.5ft
• Diameter=1-1/5=1.2
• Radius=1.2/2=0.6ft

$\\ \sf\longmapsto V=\pi r^2h$

$\\ \sf\longmapsto V=3.14(0.6)^2(20.5)$

$\\ \sf\longmapsto V=3.14(0.36)(20.5)$

$\\ \sf\longmapsto V=23.17ft^3$