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Elanso [62]
3 years ago
11

A rocket ship in space is at rest relative to a rock floating in deep space. The

Physics
1 answer:
Lesechka [4]3 years ago
5 0
So the equation used in this problem is ΔX=V0*T+1/2AT^2 the X is the distance, v0 is initial velocity, T is time, and a is acceleration. So when we plug these values it we get: 108= 0•T+1/2•3•T^2,the 0•t disappears, and the 1/2•3 gets us 1.5, so we have 108=1.5T^2, then we divide 108 by 1.5 which gets us 72=t^2, and we then take the square root and get 8.49=T so the answer is 8.49 seconds.
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To solve this problem it is necessary to apply the concepts related to the kinematic equations of motion for which the height of a particle is defined as a function of gravity as,

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There is not change in the horizontal component, therefore there is only the component horizontal given (18m/s) and the vertical component:

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Applying the vector theory to find the magnitude of a vector we have to

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Answer:

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Explanation:

Quantitative data is often gathered by using measurement tools and math.

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