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bonufazy [111]
3 years ago
8

What is the speed of a bird of mass 8kg which has kinetic energy of 8836J?

Physics
1 answer:
Kay [80]3 years ago
4 0

Answer:

For the bird moving in a straight line, the kinetic energy is one-half the product of the mass and the square of the speed: Ek=12mu2.

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WILL MARK BRAINLIEST!
boyakko [2]
It’s mass is 100 kg, because if you divide both numbers, you get 100
6 0
3 years ago
A dart is thrown horizontally with an initial speed of 10 m/s toward point P, the bull's-eye on a dart board. It hits at point Q
Kryger [21]
D=s(t) so it would be d=10(.19) d=.19 FOR BITH SNDWERS
3 0
3 years ago
If an astronaut has a mass of 16 Kg on Earth, what would be his mass on the moon and on the space station
nlexa [21]

Answer:

The astronaut's mass is 16 kg.

Explanation:

Mass can be defined as a measure of the amount of matter an object or a body comprises of. The standard unit of measurement of the mass of an object or a body is kilograms.

Irrespective of the location of an object or a body at a given moment in time, the mass (amount of matter that they're made up of) is constant. This ultimately implies that, whether you're in the moon, space, earth or any other place, your mass remains the same (constant).

Therefore, if an astronaut has a mass of 16 Kg on Earth, his mass on the moon and on the space station would remain the same, as his original mass of 16 Kg because mass is indestructible.

3 0
3 years ago
An object 5.Ocm in the length is placed at a distance of 20cm in front of convex mirror
andrew-mc [135]

Answer:

Position = \frac{60}{7}\ cm behind the mirror

Nature = Virtual and Erect

Size = \frac{15}{7}\ cm : Diminished

Explanation:

Sign convention-Distance measured to the left of pole is negative and to the right of pole is positive.

Object distance = u = -20 cm

Focal length = f = Radius of curvature/2 = 30/2 = 15 cm

We have to use mirror formula to find image distance.

\frac{1}{u}+\frac{1}{v}=\frac{1}{f}\\ \frac{1}{-20}+\frac{1}{v}=\frac{1}{15}\\ \frac{1}{v}=\frac{7}{60}\\v=\frac{60}{7}\ cm

Since the image distance is positive, it is formed behind the mirror or a virtual image is formed.

Magnification = =\frac{h_{image}}{h_{object}}=-\frac{v}{u}=\frac{60}{7\times20}=\frac{3}{7}

Height of the object = 5 cm

Height of the image = 5\times\frac{3}{7}=\frac{15}{7}\ cm

Since the height of the image is positive and less than the size of object,it is erect and diminished.

4 0
3 years ago
Give reasons.<br>a) Sunlight does not fall on the ground where cloud forms shadow.​
Viefleur [7K]

Answer:

Sunlight passing through a cloud is scattered in various directions. Some photons eventually find their way out the bottom of the cloud, some are reflected upwards, and some are absorbed, serving to warm the cloud. Since only a fraction of the light makes it to ground level, you have a shadow.

Explanation:

Hope it helps you

4 0
3 years ago
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