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bonufazy [111]
3 years ago
8

What is the speed of a bird of mass 8kg which has kinetic energy of 8836J?

Physics
1 answer:
Kay [80]3 years ago
4 0

Answer:

For the bird moving in a straight line, the kinetic energy is one-half the product of the mass and the square of the speed: Ek=12mu2.

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A person hears a siren as a fire truck approaches and passes by. The frequency varies from 480Hz on approach to 400Hz going away
alekssr [168]

Answer:

31.2 m/s

Explanation:

f_{app} = Frequency of approach = 480 Hz

f_{aw} = Frequency of going away = 400 Hz

V = Speed of sound in air = 343 m/s

v = Speed of truck

Frequency of approach is given as

f_{app} = \frac{Vf}{V - v}                           eq-1

Frequency of moving awayy is given as

f_{aw} = \frac{Vf}{V + v}                          eq-2

Dividing eq-1 by eq-2

\frac{f_{app}}{f_{aw}} = \frac{V + v}{V - v}

\frac{480}{400} = \frac{343 + v}{343 - v}

v = 31.2 m/s

7 0
3 years ago
Part B<br> Do the atoms in salt follow a pattern?
erastovalidia [21]

Answer: Yes.

Explanation: Because of the crystalline structure.

4 0
3 years ago
Which is larger, the Sun's pull on Earth or Earth's pull on the Sun?
Juliette [100K]
B it’s the most logical answer
3 0
4 years ago
A train is traveling away from you at 120 km/h. it blows its whistle, and you hear a tone of 0.400 kHz. Take the speed of sound
Vaselesa [24]

Answer:B)439.21 Hz

Explanation:

Given

velocity of train v=120 km/h\approx 120\times \frac{5}{18}=33.33 m/s

frequency of train f_a=0.400 kHz\approx 400 Hz

speed of sound c=340 m/s

frequency from Doppler effect can be calculated by

f_a=(\frac{c}{c+v})\cdot f

400=(\frac{340}{340+33.33})\cdot f

400=\frac{340}{373.33}\cdot f

f=400\times 1.098

f=439.21 Hz

5 0
3 years ago
A physics demo launches a ball horizontally while dropping a second ball vertically at exactly the same time. 1) which ball hits
Simora [160]

Answer:

Both balls will hit the ground at the same time

Explanation:

The factor which leads to ball falling is the gravity acting on the ball;

The motions along the path of both balls are independent and both balls will obey the following illustration

Using the third equation of motion

s = ut + ½at²

Where s = distance covered by both balls.

u = initial velocity of both balls. Since both balls start from rest, u = 0m/s

a = acceleration; and it's equal to acceleration due to gravity.

a = g

By substituton

s = 0 * t + ½gt²

s = 0 + ½gt²

s = ½gt²

Make t the subject of formula

gt² = 2s

t² = 2s/g

t = ±√(2s/g)

But time can't be less than 0 (in other words, negative)

So,

t = √(2s/g)

It'll take both balls √(2s/g) time to hit the floor

6 0
3 years ago
Read 2 more answers
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