The radius of the prop blade of an airplane is determined as 4.25 m.
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Radius of the prop blade</h3>
The radius of the prop blade of an airplane is calculated as follows;
a = v²/r
where;
- v is the linear speed
- r is the radius of the prop blade
- a is the centripetal acceleration
r = v²/a
r = (875²)/(180,000)
r = 4.25 m
Thus, the radius of the prop blade of an airplane is determined as 4.25 m.
Learn more about centripetal acceleration here: brainly.com/question/79801
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Air speed is how fast you are peddling over the ground, wind speed is how fast the wind is blowing above the ground.Depending on the correlation between the two with direction thrown the pilot knows what sort of resistance he is flying against.
Answer:
q2 = -1.61*10^-5 C.
Explanation:
It was given that,
F = 0.985N
q1 = +8.40 X10-6 C
q2 = ?
r = 1.11 m
k = 9 x 10^9 (standard)
It generally follows that, if force is attractive, charge will be negative.
force, F = kq1q2/r^2
0.985 = 9*10^9*8.40*10^-6*q2/1.11^2
75600q2 = 0.985*1.11^2
75600q2 = 1.2136
q2 = 1.2136/75600 = 1.60529
q2 = -1.61*10^-5 C.
By 2nd Newton's Law.
F =m*g
For 1st body
Let it's force be x
thus,
x = m*g --------- eqn 1
For mass 2,
F = 4m*g
g = F/4m -------- eqn 2
For the first body's force interms of second body substitute eqn 2 into 1
x = m*(F/4m)
x = <u>m</u><u>*</u><u>F</u>
4m
x = F/4
Therefore, the force on mass m interms of F is
F/4.
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