First, we need to think about what we're actually solving for: the area of the path. To find this, we can find the area of the whole thing, minus the area of the pool.
The diagram would look something like the picture I attached. We know that to find the area of a circle, you do πr^2. The radius is half of the diameter, so halve the diameters:
22/2 = 11 yards
32/2 = 16 yards
Then solve for the area of both circles.
π


π ≈ <span>380.13 (area of the pool)</span>
π


π ≈ <span>804.25 (area of the whole thing)
</span>
Next, subtract the area of the pool from the area of the whole thing to find the area of the walkway:

(area of the walkway)
Finally, divide the area of the walkway by 6 to see how many gallons of paint you'll need:
424.12 ÷ 6 ≈ 70.69
So you'll need 71 gallons of paint!
Hope I helped and let me know if you have any questions :)
Answer:

Step-by-step explanation:
In this graph, we have the coordinate point (
). Without translations, cos(0) = 0, which means that the graph is shifted to the right by
. We also know that the graph is shifted down by 1 because we have the point
(
), but accounting for the right shift, this point should really by (
). cos(
) = -1, but on the graph it is -2, meaning that it is shifted down by 1.
Therefore, accounting for the right shift by
and the shift down by 1, our equation is
.
Answer:
B = 1.875
Step-by-step explanation:
given that A varies directly as B and inversely as C then the equation relating them is
A =
← k is the constant of variation
to find k use the condition A = 12 when B = 3 and C = 2 , then
12 =
( multiply both sides by 2 to clear the fraction )
24 = 3k ( divide both sides by 3 )
8 = k
A =
← equation of variation
when A = 10 and C = 1.5 , then
10 =
( multiply both sides by 1.5 )
15 = 8B ( divide both sides by 8 )
1.875 = B
Answer:
x = (d + b) / (2a - c)
Step-by-step explanation:
2ax-b = cx+d
2ax - cx = d + b
x (2a-c) = d + b
x = (d + b) / (2a - c)
To find the area of the shaded region you need find the area
of the shaded region and subtract the area of the unshaded region.
Area of a rectangle = width x length
A = (x + 10) x (2x + 5)
Next apply FOIL or
First Outer Inner Last
A = (x * 2x) (x * 5) (10 * 2x) (10 * 5)
A= 2x2 + 5x + 20x + 50
A= 2x2 +25x +50
Area of a square= sides2
A= (x + 1)2
A= (x+1) (x+1)
Next apply FOIL or
First Outer Inner Last
A = (x *x) (1*x) (1*x) (1*1)
A = x2 + 1x + 1x +1
A= x2 + 2x +1
A= 2x2 +25x +50 - 2x2 +25x +50
A= 50x + 100