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mixas84 [53]
3 years ago
8

2/3 21 and 23 can best be described as 4

Mathematics
1 answer:
stich3 [128]3 years ago
6 0

Answer:

A) Vertical angles

<u>----------------------</u>

1 and 3 and 2 and 4 are vertically opposite angles or vertical angles, so option A is correct.

<u>-----------------------</u>

<u>hope it helps...</u>

<u>have a great day!!</u>

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An automatic dog feeder in the shape of a cone has a height of 18 cm. if it holds about 8,308 cm of dog food, what is the radius
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35.3

Step-by-step explanation:

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A right triangle is displayed.
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You have to use the Pythagorean Theorem to find the other side, which will be your base in the Area formula (A=1/2bh). So the Pythagorean theorem would be 36^2 + b^2 = 60^2. This gives you 48 in for your base/missing side length. Then, you plug it into the area formula. So, A=1/2(48) (36). This gives you 864 in^2 for the area of your triangle.

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What is the solution of the following system?
timama [110]

\text{Howdy!}\\\\\text{Make the x variables the same:}\\\\2(3x+2y=7)\\\\3(-2x+3/4y=-13)\\\\\\6x+4y=12\\\\-6x+2.25y=-39\\\\6.25y=-25\\\\y=-4\\\\\text{Now, plug -4 into one of the equations "y" variable}\\\\3x+2(-4)=7\\\\3x-8=7\\\\3x=15\\\\x=5\\\\\boxed{\text{Answer: (5, -4)}}

7 0
3 years ago
What is the standard form of a quadratic with a root of <br><img src="https://tex.z-dn.net/?f=2i%20%5Csqrt%7B3%7D%20" id="TexFor
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Step-by-step explanation:

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5 0
3 years ago
Simplify the sum. d^2-7d+12/d^2-d-6 + d^2+5d+6/d^2-2d-15
Law Incorporation [45]

Answer:

The sum is \frac{2d^2-5d+24}{d^2-3d-10}

Step-by-step explanation:

The given expression is


\frac{d^2-7d+12}{d^2-d-6}+\frac{d^2+5d+6}{d^2-2d-15}


These are all quadratic trinomials, so we split each of the middle terms to obtain,

\frac{d^2-4d-3d+12}{d^2-3d+2d-6}+\frac{d^2+2d+3d+6}{d^2-5d+3d-15}


We factor to obtain,


\frac{d(d-4)-3(d-4)}{d(d-3)+2(d-3)}+\frac{d(d+2)+3(d+2)}{d(d-5)+3(d-5)}


We factor further to obtain,

\frac{(d-4)(d-3)}{(d-3)(d+2)}+\frac{(d+2)(d+3)}{(d-5)(d+3)}


We cancel out the common factors to get,


\frac{(d-4)}{(d+2)}+\frac{(d+2)}{(d-5)}


The least common denominator is (d+2)(d-5).


We collect LCD to get


\frac{(d-4)(d-5)+(d+2)(d+2)}{(d+2)(d-5)}


We now expand to get,


\frac{d^2-5d-4d+20+d^2+2d+2d+4}{d^2-5d+2d-10}


We simplify to get,


\frac{d^2-9d+20+d^2+4d+4}{d^2-3d-10}


We simplify further to get,


\frac{2d^2-5d+24}{d^2-3d-10}










8 0
4 years ago
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